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marissa [1.9K]
3 years ago
6

2. (30k tiok² +5K²) 10K

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:649

Step-by-step explanation:my because I want points sorry lol

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An arithmetic sequence who's first term is -10 and the common difference is -2.
True [87]
-10,-12,-14,-16,-18......
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A coyote had 10 pups in her third litter. It was twice as many as in her second litter, her second litter, and her second litter
Yuki888 [10]
A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter

her second litter had 3 more pups than her first.( first litter +3)=2nd litter

Find the number of pups in her litter

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3xy^3 + 5- x- 2xy^3= xy^3 +11<br><br> Solve please
snow_lady [41]

Answer:


Step-by-step explanation: 3XY 3+5-X-2XY3=XY3+11  USE THE COMMUTATIVE PROPERTY TO REODER THE TERMS...3Y3+5-X-2XY3=XY3+11 COLLECT LIKE TERMS Y3+5-X-Y3X+11..Cancel equal terms on both sides of the equation 5-x=11 move constant to the right side and change its sign  -x=11-5 subtract the numbers -x=6 final answer is X=-6


8 0
3 years ago
Read 2 more answers
lucas lives 5/8 mile from school.kenny lives twice as far as lucas from school.how many miles does kenny live from school
dexar [7]
<span><span>1.       </span>Lucas Lives 5/8 miles from their schools
=> 5/8 miles is equals to:
=> 5 / 8 = 0.625 miles.
Now, the problem says that Kenny lives twice as far as Lucas from their school.
Therefore, we only need to multiply the total number of miles of Lucas distance from house to school to be able to get what is the distance of Kenny’s house to school
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3 0
3 years ago
A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th
finlep [7]

Answer:

Th computed value of the test statistic is 3.597

Step-by-step explanation:

The null and the alternative hypothesis is as follows:

Null Hypothesis:

\mathbf{H_o:} the population correlation coefficient is equal to zero

\mathbf{H_a:} the population correlation coefficient is not equal to zero

The test statistics for Pearson correlation coefficient is thus computed as :

t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }

where;

r = correlation coefficient = 0.60

n = sample size = 25

So;

t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }

t =\dfrac{0.60 \sqrt{(23)}} { \sqrt{(1-0.36} }

t =\dfrac{0.60 *4.796} {0.8}

t = 3.597

Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069

Decision Rule:

Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

Conclusion:

We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.

6 0
3 years ago
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