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Airida [17]
3 years ago
9

What is 751,447 rounded to the nearest hundred thousand?

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0

751,447 in order to round this to the nearest hundred thousands you have to ask yourself this saying about the digit just  before the number you are rounding which is 5 "five or above give it a shove four or less give it a rest"

answer 800,000


WARRIOR [948]3 years ago
4 0

Answer:

800,000.

Step-by-step explanation:

Given  : 751,447

To find : Rounded to the nearest hundred thousand?

Solution: We have given that  751,447

We can write it as  751,447

 Step 1 : Identify the hundred thousand digit 7 in 751,447

Step 2: Identify the next smallest place value 5 in  751,447.

Step 2: We can the digit equal to five , so it would be rounded up.

Step 4 : The hundred thousand 7 become increased by 1 and Every digit after becomes a zero.

Step 5 : Number become 800000.

Therefore,  800000

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Answer:

y = -1/3

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Step-by-step explanation:

3x-6y = 2    then 3x = 2+6y,   x=(2+6y)/3

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substitute for x

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reduce

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3 years ago
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4 0
3 years ago
Read 2 more answers
Need Heelppp on this question..
konstantin123 [22]

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B. Put parenthesis around 3+4. This will simplify into 7*7, giving you the correct answer, 49.

Hope this helps!

4 0
3 years ago
Write a polynomial function $f$ of least degree that has rational coefficients, a leading coefficient of 1, and the given zeros.
olganol [36]

Answer:

f(x) = x^{3} + 4x^{2} -7x^{} -10^{}

Step-by-step explanation:

The zeros of the polynomial function are given us as -5,-1,2

If the zeros of a polynomial function are α,β,ω, the polynomial function can be obtained using the expression below:

f(x) = (x - α)(x - β)(x - ω)

where α = -5, β = -1, and ω = 2

f(x)=(x-(-5) )(x -(-1))(x - 2) = (x+5)(x+1)(x-2)\\\\f(x)=(x+5)(x^{2} -2x + x -2) = (x+5)(x^{2}  -x-2)\\\\f(x)=x(x^{2}  -x-2)+5(x^{2}  -x-2)\\\\f(x)= x^{3} - x^{2} -2x + 5x^{2} - 5x - 10\\\\f(x)= x^{3} + 4x^{2} -7x - 10

<em>NB: To arrive at the answer, expand the brackets and after expansion, collect like terms to obtain the final answer</em>

4 0
3 years ago
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