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harkovskaia [24]
4 years ago
8

ABCDEFGH is a regular octagon, of side length 1cm. Calculate the exact length of AD. (Please ignore writing in pen)

Mathematics
1 answer:
Fynjy0 [20]4 years ago
5 0
Let P be the last point in the triangle you have drawn from AB.. It is isosceles and rectangle hence AB^2=2BP^2 hence AP=BP=sqrt(2).

Let Q be the last point in the triangle you have drawn from CD. By the same reasoning, CQ=DQ=sqrt(2)

What is more, AD=AP+PQ+QD=2sqrt(2)+1
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What is the range of the given function?
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Answer:

Step-by-step explanation:

x= -5,1,4,6 y=9,0,-7,-1

the range of a given function equals to the value of y in order

range = -7,-1,0,9

4 0
3 years ago
Claire has $300 Is an account. She decides she is going to take out $25 each month.
Elena-2011 [213]
Recursive equation would be f(x+1) = f(x) - 25 with f(0) = 300

Explicit equation would be f(x) = -25x + 300

And graph would looks like this: 

5 0
4 years ago
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The area of the kite is 30 m2. What is the value of x? Explain
astra-53 [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
A cup of coffee with temperature 155degreesF is placed in a freezer with temperature 0degreesF. After 5 ​minutes, the temperatur
Leviafan [203]

Answer:

45.50° F

Step-by-step explanation:

As per Newton's law,

T(t) = T_{s}+(T_{0} + T_{s})e^{-kt}

When T(t) is the final temperature

T_{s} = Temperature of surrounding

T_{0} = Initial temperature

t =duration of cooling

k = constant

103=0+(155-0)e^{-k\times 5}

103=155e^{-5k}

Now take natural log on both the sides

ln(103)=ln(155e^{-5k})

ln(103)=ln(155)+ln(e^{-5k})

ln(103)=ln(155)=-5k

4.6347 - 5.0434 = -5k

k=\frac{0.40872}{5}

k = 0.0817

T(t)=0+(155-0)e^{(0.0817\times 15)}

   = 155e^{-1.226}

   = 155 (02935)

  = 45.49 ≈ 45.50° F

8 0
4 years ago
Find an expression which represents the difference when (-3x + 5y) is subtracted
lubasha [3.4K]

Step-by-step explanation:

-3x+5y-(-6x)+3y

-3x+5y+6x+3y

-3x+6x+5y+3y

3x+2y.

8 0
3 years ago
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