1. √48 → √16 * √3 = 4√3
3. √12 → √4 * √3 = 2√3
7. √125 → √25 * √5 = 5√5
8. √20 → √4 * √5 = 2√5
9. √18 → √9 * √2 = 3√2
10. √32 → √16 * √2 = 4√2
11. √50 → √25 * √2 = 5√2
12. √27 → √9 * √3 = 3√3
Answer : 0.0129
Step-by-step explanation:
Given : Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is
years and standard deviation is
years.
Sample size : 
Let X be the random variable that represents the age of fleets.
We assume that the ages of the fleets of the 10 largest U.S. commercial passenger carriers are normally distributed.
For z-score,

For x=14

By using the standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be :-

Hence, the required probability = 0.0129
the shortest side is always opposite the smallest angle.
In triangle ABC the shortest side is AC
In triangle ADC the shortest side is DC
DC<AC since they are in the same triangle.
Hello,
Here is the formula to find the area of the trapezoid:
A=1/2(b1+b2)×h
Where b1 represent big base
b2 represent small base
and h represent height
Now, we just need to replace the number to get the final answer:
A=1/2(16.8+6.9)×2
A=1/2(23.7)×2
A=23.7 square yards. As a result, the area of the trapezoid is 23.7 square yards. Hope it help!
Answer:
Explained below.
Step-by-step explanation:
The data provided is for the dying time of four different types of paint.
One-way ANOVA can be used to determine whether all the four paints have the same drying time.
Use Excel to perform the one-way ANOVA.
Go to Data → Data Analysis → Anova: Single Factor
A dialog box will open.
Select the data.
Select "Grouping" as Columns.
Press OK.
The output is attached below.
The required values are as follows:
(1)
Sum of Squares of Treatment (Between Subjects):
SST = 330
(2)
Sum of Squares of Error (Within Subjects):
SSE = 692
(3)
Mean Squares Treatment (Between Subjects):
MST = 110
(4)
Mean Squares Error (Within Subjects):
MSE = 43.25