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kenny6666 [7]
3 years ago
6

Write an equation in point-slope form for the line through the given point with the given slope.

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

y+7= -6/5(x+3)

Step-by-step explanation:

Point slope form for a line is given by

y-y1 = m(x-x1) where m is the slope and (x1, y1) is a point on the line

y - -7 = -6/5(x - -3)

y+7= -6/5(x+3)

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Answer:  just want points tbh

Step-by-step explanation:

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What is the measure of angle X. No links plz
Usimov [2.4K]

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30

Step-by-step explanation:

4 0
3 years ago
The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
You are walking along a path y= 2x + 12 and your
UNO [17]

Answer:

(-1,10)

Step-by-step explanation:

At the point when the paths cross, the respective x and y values of each equation will be equal.

Your path is y=2x+12, and your friends path is 4x+y=6. Sub 2x+12 in for y (from your path's equation) into your friends equation to find the value of x:

4x+2x+12=6

6x=-6

x=-1

y=2x+12

y=2(-1)+12=10

So you will cross paths at (-1,10)

3 0
3 years ago
The sum of three numbers is 113 . The second number is 3 times the third. The first number is 7 less than the third . What are t
OLga [1]
Number 1 = 17
number 2 = 72
number 3 = 24


work:

the three numbers are symbolized as x, y, and z

x + y + z = 113

number 2 (y) is 3 times the third number (z) so 

y = 3z

so x + 3z + z = 113

the first number (x) is 7 less than than the third number (z) so

x = z - 7

so z -7 + 3z + z = 113

5z - 7 = 113
5z = 120

z = 24

x = 17
y = 72

Hope this helped :)
8 0
3 years ago
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