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valkas [14]
3 years ago
14

How many times shorter is one foot then one yard

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
5 0
1yd is 12 ft

So do 12-1=11.

11 is the answer
barxatty [35]3 years ago
5 0

Answer:

Hence, 1 foot is 2 feet shorter than 1 yard

Step-by-step explanation:

We have to determine how many times shorter is one foot then one yard.

We know that 1 yard=3 feet

1 foot=(3-2) feet

1 foot=3 feet-2 feet

1 foot=1 yard-2 feet

Hence, 1 foot is 2 feet shorter than 1 yard

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The example of a beach ball with a ping pong ball inside of it can be used to imagine the relationship between what two entities
Nookie1986 [14]

The celestial sphere and Earth is the example of a beach ball with a ping pong ball inside of it can be used to imagine the relationship between what two entities.

The heavenly sphere is what Why is this old idea still relevant today?

  • Ancient people used the celestial sphere to describe the visible universe.
  • Although our understanding of the cosmos has changed, the concept of a celestial sphere is still prevalent because it provides a straightforward perspective on the stars that is useful for navigation.

Which phrase most accurately sums up the celestial sphere?

The entire sky as seen from Earth is portrayed by the celestial sphere. Keep in mind that the celestial sphere is intended to depict the sky as it appears from our planet rather than physical reality.

Learn more about celestial sphere

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3 0
1 year ago
Convert 490 square meters to square dekameters<br> please show work, if you can't thats okay
Savatey [412]
The answer will be 4.9. =) 

Since we know 1 metre is 0.01 dekametres, we can use this to answer the question!

We simply multiply 490 by 0.01. =)
5 0
2 years ago
Read 2 more answers
Simone, buys one charger for $ 1.59 and phone popsockets $0.29 for each. She spends a total of $5.07. If there is no sales tax a
Arisa [49]

Answer:

it is B i took the quiz

Step-by-step explanation:

hope it helps

3 0
3 years ago
&lt;EFG and &lt;GFH are a linear pair, m&lt;EFG = 4n + 17, and m&lt;GFH = 5n + 19.
nlexa [21]
What I don’t understand that what subject is this????
7 0
3 years ago
A population of protozoa develops with a constant relative growth rate of 0.469 per member per day. On day zero the population c
garik1379 [7]

If the growth rate is 0.469 per member per day and in the beginnning there are 5 members then the population size after eight days is 108.42.

Given growth of population of protozoa 0.469 per member per day and population in beginninng is 5 members.

We have to find the population afte eight days.

First of all we have to find the function or equation showing sum of population after t days.

Because it is given that the rate is 0.469 per member per day it means it is like compounding.

The equation which shows the sum after compounding is P(1+r)^{n}

where P is the amount in beginning, r is the rate and n is the number of years.

In this problem the equation will be 5(1+0.469)^{t} where t is number of days.

We have to put the value of t=8 to find the population after 8 days=

=5(1.469)^{8}

=5*21.68

=108.42

Hence the population of protozoa after 8 days is 108.42.

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4 0
1 year ago
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