The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
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Answer:
SB or ? = 9
Step-by-step explanation:
Since the two triangles are similar.
((18 + 6) / 6) = 24 / 6 = <u>4</u>
[Scale factor between ∆BCU and ∆SUT]
SB or ? = 12 – 12/<u>4</u> = 12 – 3 = 9
Just try Google or calculator millions of sites simplify it
