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3 years ago

Solve the equation by completing the square. round to the nearest hundredth if necessary. x^2+3x-5=0

Mathematics

1 answer:

elena55 [62]3 years ago

3 0

X=0.85 and -5.85 is the answer, that's all of the work

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Proportions, assist me please!

Anit [1.1K]

Step-by-step explanation:

$w = \frac{1}{2} {x}^{2} y \\ (2)w = \frac{1}{2} {x}^{2} y(2) \\ 2w = {x}^{2} y \\ \frac{2w}{ {x}^{2} } = \frac{{x}^{2} y}{ {x}^{2} } \\ \frac{2w}{ {x}^{2} } = y$

<h3>Answer:</h3>

$y = \frac{2x}{ {x}^{2} } \\$

6 0

3 years ago

How do I solve this

pashok25 [27]

Answer: Buses 385

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2 years ago

234 is 45% of what amount

GaryK [48]

Answer:

520?

Step-by-step explanation:

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2 years ago

A bee flies 25 m north of the hive then 10 m east 5 m west and 10 m south. How far north and east of the hive is it now? Explain

mafiozo [28]

Answer:

20 meters north.

Step-by-step explanation:

(I did it on a paper not to lose track.) First we go 25 north. Then ten east. Five south. And 10 west again. So in East/West we didn't move but we moved 5 down/south so we are still at twenty. If you don't understand still draw it on a paper.

5 0

2 years ago

52 regular playing cards are randomly dealt to four players with each players receiving 13 cards. What is the probability that e

Vadim26 [7]

Answer:

The probability is 1/28,561

Step-by-step explanation:

Here, we want to find the probability that each of the players will receive exactly one ace.

In a deck of cards, we have 4 suites of 13 cards each, with each of the suites consisting of 1 ace.

So, the probability of getting an ace for each of the four players will be 4/52 = 1/13

Now, the probability of each of the players getting exactly one ace will be; first got one ace , second got one , third got one and fourth got one.

mathematically, this probability will be 1/13 * 1/13 * 1/13 * 1/13 = (1/13)^4 = 1/28,561

7 0

3 years ago