3x^2 - 7x + 12 = 0 ....subtract 12 from both sides
3x^2 - 7x = -12 ....divide both sides by 3 to get x^2 by itself
x^2 - 7/3x = -4
His work is not accurate because he divided the second term by 4 instead of 3.
Answer: The unit circle contains values for sine, cosine, and tangent.
Step-by-step explanation: The coordinates on the unit circle are the sine ratio and cosine ratio. From this, the tangent, secant, cosecant, and cotangent can be found.
Hey there!
You can use distributive property, as I mentioned in your previous questions.
multiply...
2a² × a = 2a³
2a² × -1 = -2a²
a × a = a²
a × -1 = -a
3 × a = 3a
3 × -1 = -3
add all those terms..
2a³ - 2a² + a² - a + 3a - 3
add the like terms
2a³ - a² + 2a - 3
Hope this helped :)
Answer:
not helping you i will take the points tho.
Step-by-step explanation:
thanks for the points im taking them back now c: this is what you get for messing with me
Question 1:
Since the triangles are congruent, we know that QS = TV
This means that
3v + 2 = 7v - 6
Subtract both sides by 2
3v = 7v - 8
Subtract 7v from both sides
-4v = -8
Divide both sides by -4
v = 2
Plug this value back into 3v + 2 and you get 8.
QS = 8
Since the triangles are congruent
QS = 8 AND TV = 8
Question 2:
So we know that AC = AC because that's a shared side.
It's also given that BC = CD.
In order for two triangles to be congruent by SAS, the angle between the two sides must be congruent.
That means angle C must be congruent to angle C from the other triangle.
Question 3:
We know that AC = AC because it's a shared side.
We also know that angle A from one triangle is equal to angle C from the other.
However, for a triangle to be congruent by SAS, the congruent angle must be between two congruent sides.
In order for us to prove congruence by SAS, AD must be congruent to BC.
Have an awesome day! :)
