Answer:
D. to minimize the sum of setup cost and holding cost e. to calculate the optimum safety stock
Explanation:
Economic order quantity ( EOQ ) is formulated as :
![EOQ= \sqrt[]{\frac{2C_O D}{C_h} }](https://tex.z-dn.net/?f=EOQ%3D%20%5Csqrt%5B%5D%7B%5Cfrac%7B2C_O%20D%7D%7BC_h%7D%20%7D)
Co = Ordering cost
D = annual demand
Ch = Annual unit holding cost
Economic quantity is the order quantity which minimizes sum of annual cost of ordering and annual inventory holding cost so to minimize the overall cost of the inventory.
ANSWER : d) to minimize the sum of setup cost and holding cost that is to calculate the optimum safety stock.
The answer is A. This is the only grassland competition.
The answer is C, twisted ladder
My mom always say when in dought pick C so C
Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type possible genotypes
Type A AA, AO
Type B BB, BO
Type AB AB
Type O OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired homozygous smooth haired
P gen SS x ss
F1 gen. Ss
phenotype: wire haired
