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ankoles [38]
3 years ago
14

How do I solve n x 721= 72.1 and .074 x n = 74

Mathematics
1 answer:
erica [24]3 years ago
4 0
N x 721 = 72.1
721n = 72.1 (put it in an easier format)
n = 0.1 (divide both sides by 721)

0.074 x n = 74
0.074n = 74 (put it in an easier format)
n = 1000 (divide both sides by 0.074)

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Pretty sure it is D.

Step-by-step explanation:

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In a video game, Clare scored 50% more pints than Tyler. If c is the number of points that Claire scores and t is the number of
olga55 [171]
<h3><u>Question:</u></h3>

In a video game, Clare scored 50% more points than Tyler. If c is the number of points that Clare scored and t is the number of points that Tyler scored, which equations are correct? Select all that apply.

the options are

A. c=1.5t

B.c=t+0.5

C. c=t+0.5t

D. c=t+50

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<h3><u>Answer:</u></h3>

Options A, C, E are correct

The correct equations are c = 1.5t and c = t + 0.5t and c = (1 + 0.5)t

<h3><u>Solution:</u></h3>

Let "c" be the number of points clare scored

Let "t" be the number of points tyler scored

Given that,

Clare scored 50% more points than Tyler

Points scored by clare = points tyler scored + 50% of Tyler points

c = t + 50 % of t

Therefore, on solving, we get

c = t + \frac{50}{100} \times t\\\\c = t + 0.5t

Thus option c is correct

On simplfying we get,

c = t + 0.5t = 1.5t

c = 1.5t

Thus option A is correct

c = t + 0.5t

On taking "t" as common we get,

c = t(1 + 0.5)

Thus option E is also correct

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4 years ago
Newton’s law of cooling states that dx/dt= −k(x − A) where x is the temperature, t is time, A is the ambient temperature, and k
Vadim26 [7]

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

(b) The initial condition t > 0 will not make much of a difference.

Step-by-step explanation:

Given the differential equation

dx/dt= −k(x − A); t > 0, A = A_0Coswt

(a) To solve the differential equation, first separate the variables.

dx/(x - A) = -kdt

Integrating both sides, we have

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x = A + Ce^(-kx)

Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

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