All categories

3 years ago

How do I solve n x 721= 72.1 and .074 x n = 74

1 answer:

4 0

N x 721 = 72.1
721n = 72.1 (put it in an easier format)
n = 0.1 (divide both sides by 721)

0.074 x n = 74
0.074n = 74 (put it in an easier format)
n = 1000 (divide both sides by 0.074)

You might be interested in

Hest answer = Brainilest

Assoli18 [71]

Answer 116•6 feet

Hope it is helpful

4 0

2 years ago

Solve for x. Assume that lines are diameters?

Delicious77 [7]

360 - 20 + 2x = 360
340 + 2x = 360
2x = 20
x = 10

5 0

3 years ago

Read 2 more answers

A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati

I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

$T=72-20e^{-0.08t}$

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

$\frac{dT}{dt}=k*(T_r-T)$

If we rearrange and integrate

$\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}$

We know that at time 0, the temperature of the drink was 52°F. Then we have:

$T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20$

We also know that at t=2, T=55°F

$T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08$

The model for the temperature of the drink can be written as

$T=72-20e^{-0.08t}$

7 0

4 years ago

If the average, mode, and range of 5 different numbers are all 8, find the sum of all possible values of the second largest numb

ANTONII [103]

I believe you meant:

If the average, mode, and range of 5 different numbers are all 8, find the sum of all possible values and the second largest number

Answer:

Sum of all possible values = 40

Second largest number= 8

Explanation:

Since our mean, mode, and range is 8, our sum is 40 and our second largest number is 8.

The sum of all the numbers is 40 since our mean is 8 and there are 5 numbers(8×5)

To find possible values, we already know the mode is 8 and so we know 8 must appear more than once. If we have 8 twice then we are left with 24(sum is 40). We have 3 numbers left and the range is 8 so we must have a maximum number and minimum number that has a difference of 8 and a third number, all adding up to 24(sum left). Within 24, only 12-4+8 satisfies the condition, hence our numbers are: 4,8,8,8,12.

3 0

3 years ago

+3c - 7d <br> - 2c + 5d <br> - c + 8d <br> +4c - 6d<br> ______

ollegr [7]

*Hint: You must combine like terms and solve.

3c - 7d - 2c + 5d - c + 8d + 4c - 6d
7c - 3c + 13d - 13d
4c

3 0

4 years ago