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LuckyWell [14K]
3 years ago
15

Newton’s law of cooling states that dx/dt= −k(x − A) where x is the temperature, t is time, A is the ambient temperature, and k

> 0 is a constant. Suppose that A A0 cos(ωt) for some constants A0 and ω. That is, the ambient temperature oscillates (for example night and day temperatures).a. Find the general solution.b. In the long term, will the initial conditions make much of a difference? Why or why not?
Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

(b) The initial condition t > 0 will not make much of a difference.

Step-by-step explanation:

Given the differential equation

dx/dt= −k(x − A); t > 0, A = A_0Coswt

(a) To solve the differential equation, first separate the variables.

dx/(x - A) = -kdt

Integrating both sides, we have

ln(x - A) = -kt + c

x - A = Ce^(-kt) (Where C = ce^(-kt))

x = A + Ce^(-kx)

Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

And we have the solution.

(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).

It is not any different from when t < 0.

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Jackson sold 27 pounds of bananas and 12 pounds of grapes.

Given that Jackson runs a farm stand that sells bananas and grapes, and each pound of bananas sells for $ 1 and each pound of grapes sells for $ 2.25, and Jackson sold 15 more pounds of bananas than pounds of grapes and made $ 54 altogether, to determine the number of pounds of bananas sold and the number of pounds of grapes sold the following calculation must be performed:

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