Answer:
x = 11√2
Step-by-step explanation:
We can notice the triangle given is a special triangle, a 45°- 45°- 90° triangle. The hypotenuse of a 45°- 45°- 90° is √2 times the length of a side. We can set up the equation(using x as the side):
x * √2 = 22
We can divide by √2 on both sides to get:
x = 22 / √2
To rationalize the denominator, we multiply by √2 / √2 on the right side:
x = 22√2 / 2
This simplifies to:
x = 11√2
Well that would be 8 apples in 4 bags so there’s 6
answer: 6
Answer:
Equation: 
Step-by-step explanation:
<em>The question is incomplete as the dimension of the phone was not given.</em>
<em>However, the following explanation will guide you</em>
Given
Required
Determine the Height
Volume is calculated as thus;
Substitute 75 for Volume
Divide through by Area
<em>The above represent the equation to solve for Height</em>
<em>To solve for height, we need the dimension of the phone or the area.</em>
Take for instance; the length and width of the phone is 5 by 5 inches;
The height would be:
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
For the first equation, the answer is C) completing the square.
For the second equation, the answer is B) zero product property.
For the first equation, we can easily complete the square by finding half of b and squaring it; then we can take the square root of both sides and solve the equation.
For the second equation, since it is already factored, we use the zero product property to solve it.
