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3 years ago

I can’t figure this out

Mathematics

1 answer:

patriot [66]3 years ago

7 0

Answer:

$m \leq 4.3$

Step-by-step explanation:

We need to get m on one side all by itself. To achieve this, let's subtract both sides by 1.2 to get $m \leq 5.5-1.2 \implies m \leq 4.3$ .

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Please help I will give 10 points answer both questions

seropon [69]

Question 4:
18(A)+7(S)+10(G)=35 lollipops
35/10=3.5
35/18=1.99(repeating)
35/7=5

I hope that helps in some way.

5 0

3 years ago

What is the value of x? 40° (6x + 2)

Anvisha [2.4K]

Answer:

x = 8

Step-by-step explanation:

40 + 6x + 2 = 90 {Complementary angles}

Combine like terms

40+ 2 + 6x = 90

42 +6x = 90 {Subtract 42 form both sides}

6x = 90 - 42

6x = 48 {divide both sides by 6}

6x/6 = 48/6

x = 8

6 0

3 years ago

Read 2 more answers

Which equation represents the line that passes through (-8,11) and

Elena-2011 [213]

Answer:

A) y = -5/8x + 6

Step-by-step explanation:

y2 - y`1 / x2 - x1

7/2 - 11 / 4 - (-8)

-15/2 / 12

= -5/8

y = -5/8x + b

11 = -5/8(-8) + b

11 = 5 + b

6 = b

4 0

3 years ago

Read 2 more answers

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.