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3 years ago

I can’t figure this out

Mathematics

1 answer:

patriot [66]3 years ago

7 0

Answer:

$m \leq 4.3$

Step-by-step explanation:

We need to get m on one side all by itself. To achieve this, let's subtract both sides by 1.2 to get $m \leq 5.5-1.2 \implies m \leq 4.3$ .

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the riding lawn mower that alejandro has on his farm has the top speed of 8 km/h. What is a lawn mowers top speed in meters per

Dimas [21]

Since 1 km = 1000 m, the lawnmowers top speed would be 8000 m/h.

8 0

3 years ago

Read 2 more answers

Aldo takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit

stealth61 [152]

Let Y = total cost of both schools.

The total cost would be ( number of credits at Westside x 98) + (number of credits at Pinewood x 115).

The total number of credits he is taking is 14.

If w is the number of credits at Westside, then for Westside you have 98w ( $98 times the number of credit hours)

The equation is now y = 98w + (number of credits at Pinewood x 115).

The number of credit hours at Pinewood would be the total credit hours 14 minus the credit hours at Westside w, so you have 14-w, which needs to be multiplied by the cost at Pinewood.

The equation is now y = 98w + 115(14-w)

This can be simplified using the distributive property to:

Y = 98w + 1610 - 115w

Y = -17w + 1610

6 0

3 years ago

Could somebody help me with Geometry? THANKS!!!!!!!!!!!!!!!!!!!!!

Vedmedyk [2.9K]

I'll do problem 1 to get you started.

The answer to problem 1 is <u>3400 miles</u>

============================================================

Explanation for problem 1:

We're asked to find the perimeter, which is the total distance around the exterior or outside. In other words, we need to add up the four side lengths of this quadrilateral.

We'll need the distance formula to find the lengths of the slanted sides AB and BC

----------------------------------------

Let's first find the length of segment AB

A = (x1,y1) = (0,0)

B = (x2,y2) = (400,300)

d = Length of AB

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-400)^2 + (0-300)^2}\\\\d = \sqrt{(-400)^2 + (-300)^2}\\\\d = \sqrt{160000 + 90000}\\\\d = \sqrt{250000}\\\\d = 500\\\\$

The distance from A to B is 500 miles. This is the same as saying segment AB is 500 miles long.

----------------------------------------

Now find the length of segment BC

B = (x1,y1) = (400,300)

C = (x2,y2) = (-800,800)

d = length of BC

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(400-(-800))^2 + (300-800)^2}\\\\d = \sqrt{(400+800)^2 + (300-800)^2}\\\\d = \sqrt{(1200)^2 + (-500)^2}\\\\d = \sqrt{1440000 + 250000}\\\\d = \sqrt{1690000}\\\\d = 1300\\\\$

----------------------------------------

The length of CD is fairly easy to find without needing the distance formula. This is because it is a vertical line. We subtract the y coordinates of C and D to get 800-0 = 800. So CD is 800 miles long.

Segment DA is a similar story. But we subtract the x coordinates. This only works for horizontal lines. DA is 800 miles long because |-800-0| = 800. Absolute value is used to make sure the distance is never negative.

----------------------------------------

To summarize everything so far, we found these four side lengths

AB = 500
BC = 1300
CD = 800
DA = 800

The perimeter is going to be the sum of those four sides, leading to...

perimeter = sum of sides

perimeter = AB+BC+CD+DA

perimeter = 500+1300+800+800

perimeter = 3400 miles

This is the total distance traveled if you started at city A, went to B, then to C, then to D, and then finally went back to A.

5 0

2 years ago

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how is building a triangle with different side lengths given different than building a quadrilateral with given side lengths?

Mariana [72]

Answer:

there can only be one possibility for a triangle when given the lengths of all the sides but for a quadrilateral the measure of the angles could differ depending on the person building the,. this is because triangles are more stable than quadrilaterals meaning that their side lengths follow a lot more rules than quadrilaterals do, for example the length of the side lengths can indicate whether or not that triangle is an acute, obtuse, or right triangle, and this is also evident by considering that you can use the SSS theorem to indicate two triangles are congruent, but for quadrilaterals you cant do that

Step-by-step explanation:

8 0

3 years ago

Soooo yea uh i need help :'3 <br> 2 1/3 feet :4 1/2 feet <br> help

denpristay [2]

$2 \frac{1}{3} : 4 \frac{1}{2} \\ = \frac{7}{3} : \frac{9}{2} \\ = 14:27$

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2 years ago