Let 
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so
where 
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is
where 
denotes the CDF of , and 
denotes the inverse CDF. We have
Similarly, because 20% of students obtain less than 40 marks, we have
so that
Then 
are such that
and we find
Answer:
Domain: x ≥ 0
Range: All real numbers
Step-by-step explanation:
This is an absolute value function which creates a V for its graph. Since the absolute value is on y, the function is rotated to the right or sideways.
This means only the x values of 0 and greater are used in the function. Since the domain is the set of all x values then it is x≥0.
This also means that all y values are used on the y-axis. There is no restriction on the y values. Since the range is the set of all y values then it is all real numbers.
The answer would be A = 54raiz (3) + 18raiz (91)
Formula:
A = Ab + Al Where, Ab=base area A= lateral area
The area of the base is: Ab = (3/2) * (L ^ 2) * (root (3)) Where, L= side of the hexagon. Substitute: Ab = (3/2) * (6 ^ 2) * (root (3)) Ab = (3/2) * (36) * (root (3)) Ab = 54raiz (3)
The lateral area is: Al = (6) * (1/2) * (b) * (h) Where, b= base of the triangle h= height of the triangle Substitute: Al = (6) * (1/2) * (6) * (root ((8) ^ 2 + ((root (3) / 2) * (6)) ^ 2)) Al = 18 * (root (64 + 27)) Al = 18raiz (91)
The total area is: A = 54raiz (3) + 18raiz (91)
Let N be the number of items sold and p the price.
Since the variation is inverse, then the relation between N and p is:
For N=20000 and p = $9.5, we get the formula:
If p = 8.75, then the number of items sold can be computed using the formula:
