I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Answer:
Algebra
Step-by-step explanation:
60g/12miles = 5g/mile
So, 1200g / 5g = 240 miles
Answer:
(4 , 3 ) and (-3 , -4)
Step-by-step explanation:
Other two vertices will be in 1st quadrant and 3 rd quadrant
Answer:
Step-by-step explanation:
The proportion that Alan solved was
x/200 = 8/25
His working as shown was
(8)(x) = (25) (200)
8x = 5000
He divided both sides of the equation by 8. It became
8x/8 = 5000/8
x = 625
The correct steps are
25x = 200 × 8 = 1600
Dividing both sides of the equation by 25, it becomes
x = 1600/25
x = 64
Alan's error were:
1) He got the wrong product when he multiplied 25 by 200.
2)He got the wrong quotient when he divided 5,000 by 8.