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trapecia [35]
3 years ago
13

3. There are 7 gray kittens. 2 kittens are black. How many less black kittens are there than gray kittens?

Mathematics
2 answers:
gregori [183]3 years ago
8 0
It is basic math. If there are seven gray kitten, and 2 black kittens. There is a five kitten difference between the gray and black. Your answer is 5.
galben [10]3 years ago
7 0
There are 5 less black kittens than there are gray. 7 - 2 = 5
Hope this helps! Let me know if you need any further assistance!
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Murljashka [212]

Answer:

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Step-by-step explanation:

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PLEASE HELP!!!
MakcuM [25]

Answer:

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Step-by-step explanation:

x + y =6

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D. 2+4 equals 6 but 2-4 doesn't equal 4

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Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] < y0 < [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

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Alina [70]

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The total number of possibilities is

                   (26 x 26 x 10 x 10 x 10 x 10 x 10) =

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