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nalin [4]
3 years ago
10

Help me what to write a word phrase for each algebraic expression

Mathematics
1 answer:
Luda [366]3 years ago
5 0
The first on is 5 added to q
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What numbers come next? 11, 14,17,20 A 24,28,32 B 23, 26,29 C 23, 27, 31 D25,30,35
ArbitrLikvidat [17]

Answer:

B

Step-by-step explanation:

The answer is B (23, 26, 29) because you are adding 3 after each step.

Hopes this helps.

4 0
3 years ago
Hi I’ll appreciate it if you help me!
dexar [7]
The answer would be 30in.
Reasoning: if the two figures are proportional, you would set it up in a proportion. It would be 36/x=12/10. Then cross multiply, so it would be 12x and 36(10). Afterwords you’ll have 12x=360, then divide both sides by 12 and you’ll end up with 30.
4 0
3 years ago
An open box of maximum volume is to be made from a square piece of material 24 cm on a side by cutting equal squares from the co
mr Goodwill [35]

Answer:

V = x(24 - x)^2 cm^3.

Domain = (0, 24).

Step-by-step explanation:

a. Let the lengths of the sides of the squares be x cm.

Then the lengths of the sides of the base of the box will be  (24 - 2x) cm.

The height of the box will be x cm.

So the required volume

= height * area of base

So V = x(24 - x)^2

b. The domain of this function is (0, 24).

5 0
3 years ago
A seafood restaurant claims an increase of $1,750.00 over its average profit during a week where it introduced a special of bake
kolezko [41]
I belive B. is 700$, for the rest i dont know
8 0
3 years ago
Help, please! This is due tomorrow evening! Show work, please! Will give brainliest!
Maru [420]

Answer:

h = height reached

-16 t^2 = 1/2 g t^2 where g = 32 ft/sec^2

v t = height due to original vertical speed v

s = initial height

1. -45 = -16 t^2 + 62 t + 0         measuring height from original height

solving quadratic

2. t = 4.5 sec

3. time to reach max height = v / g = 62/32 = 1.94 sec

H (above release point) = -16 (1.94^2) + 62 * 1.94 = 60 ft

4. 2 * 1.94 = 3.88    solved in part 3

5. 1.94   solved on part 3

Check:  time to fall 60 + 45 ft = 105 ft

105 = 1/2 g t^2

t = (210 / 32)^1/2 = 2.56 sec

total time = 2.56 * 1.94 = 4.5 sec     time to fall + rise time

-45 = -16 * 4.5^2 + 62 * 4.5

-45 = -324 + 279 = -45        checking time to reach -45 feet using given equation

4 0
2 years ago
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