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Mariulka [41]
2 years ago
15

Which of the following stanements shows the inverse property of addition?

Mathematics
1 answer:
Nikitich [7]2 years ago
4 0

Answer:

0\cdot \:y+\left(-0\cdot \:y\right)=0  the  statement shows the inverse property of addition as the sum of a number and its inverse is zero.

Step-by-step explanation:

As we know that Inverse Property of Addition states if you add any number to its opposite, the result will be zero.

For example, 13 + (-13) = 0 shows that -13 is the additive inverse of 13.

In other words, the sum of a number and its inverse is zero.

Now checking from the available options,

0y+\left(-0y\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=0\cdot \:y-0\cdot \:y

\mathrm{Add\:similar\:elements:}\:0\cdot \:y-0\cdot \:y=0

=0

Thus,

0\cdot \:y+\left(-0\cdot \:y\right)=0

Therefore, 0\cdot \:y+\left(-0\cdot \:y\right)=0  the  statement shows the inverse property of addition as the sum of a number and its inverse is zero.

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Answer:

<em><u>x=2, y=4</u></em> (as a point,) (2, 4)         (last part is unnecessary unless you are graphing)

Step-by-step explanation:

Use substitution.

Substitute y for 2x.

Since y=2x, you can plug 2x into the place where y goes...

Instead of y=-1/2x+5

2x=-1/2x+5....Now solve

2.5x=5 (Sorry my computer cannot type fractions very clearly)

/2.5    /2.5        (dividing by 2.5 on both sides)

<u><em>x=2</em></u>

Now just plug x into any of the equations to find y (preferably the easier one).

y=2x becomes

y=2*(2)

=4

<em><u>y=4</u></em>

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when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%​

  • Selling price = cost price - discount ⇒ discount case
  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by \frac{16}{9} to find x

∵ 0.8x = \frac{16}{9}

- Divide both sides by 0.8

∴ x = \frac{20}{9}

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

∵ Profit = 20% × \frac{20}{9} = \frac{20}{100}.\frac{20}{9}=\frac{4}{9}

- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0
3 years ago
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