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Dima020 [189]
3 years ago
5

Find the angle between the given vectors to the nearest tenth of a degree.

Mathematics
2 answers:
GalinKa [24]3 years ago
7 0

Answer:

1.8°

Step-by-step explanation:

u = <6,4> , v = <7,5>

Magnitude of u

|u|=\sqrt{6^2+4^2}\\\Rightarrow |u|=\sqrt{36+16}\\\Rightarrow |u|=\sqrt {52}

Magnitude of v

|v|=\sqrt{7^2+5^2}\\\Rightarrow |u|=\sqrt{49+25}\\\Rightarrow |u|=\sqrt {74}

cos\alpha =\frac{u.v}{|u|\ |v|}\\\Rightarrow cos\alpha =\frac{6\times 7+4\times 5}{\sqrt {52} \sqrt {74}}\\\Rightarrow cos\alpha =0.99948\\\Rightarrow \alpha =cos^{-1}0.99948\\\Rightarrow \alpha =1.847^{\circ}

∴ Angle between the vectors is 1.8°

Volgvan3 years ago
6 0
Α=arctan(5/7)≈35.5°

ß=arctan(4/6)≈33.7°

α-ß≈1.8°


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Answer:

a. =11+ 1

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Step-by-step explanation:

a. 20 - 9 + 8 -7

=11+ 1  ( this is obtained by solving)

b. 4x - 7y - 5z + 6

=4x+ (-7y) + (-5z) +6

We multiply the negative sign with the positive sign to get a minus so the answer remains the same and the expression is written as an addition sum.

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-[ 3x+8y+4+8/7z]

or

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The minus sign is taken as common leaving the expression with the plus only.

It can be written in the same manner as above, adding the negative terms so that the expression is written as a sum.

3 0
2 years ago
An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin
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