What is the length of side AC of the triangle?
1 answer:
Answer:
AC = 25 units
Step-by-step explanation:
Given ∠ A = ∠ C then the triangle is isosceles and BC = AB , that is
7x - 1 = 5x + 5 ( subtract 5x from both sides )
2x - 1 = 5 ( add 1 to both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Then
AC = 6x + 7 = 6(3) + 7 = 18 + 7 = 25 units
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Step-by-step explanation:
Answer:
30/(2x^2-x)
Step-by-step explanation:
5/(2x-1) * 6/x
Multiply the numerators
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Multiply the denominatos
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