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2 years ago

Simplify (-8y^2+6y-1)+(-8y^2+8y+1)(-3y^2+9y-9)

Mathematics

1 answer:

KonstantinChe [14]2 years ago

7 0

Answer:

$24y^4-96y^3+133y^2-57y-10$

Step-by-step explanation:

Given expression

$(-8y^2+6y-1)+(-8y^2+8y+1)(-3y^2+9y-9)$

First, multiply two polynomials in brackets:

$(-8y^2+8y+1)(-3y^2+9y-9)\\ \\=24y^4-72y^3+72y^2-24y^3+72y^2-72y-3y^2+9y-9\\ \\=24y^4-96y^3+141y^2-63y-9$

No add two polynomials:

$-8y^2+6y-1+24y^4-96y^3+141y^2-63y-9\\ \\=24y^4-96y^3+133y^2-57y-10$

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A recipe calls for 2 cups of oats and 4 cups of flour. Alicia makes a larger batch mixing 4 cups of oats and 6 cups of flour. Di

ValentinkaMS [17]

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3 years ago

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ABC form a triangle where BAC equals 90° a B equals 10.8 mm and C equals 1.6 mm find the length of BC give your answer rounded t

Marysya12 [62]

Answer:

BC = 10.9 mm

Step-by-step explanation:

The computation of the BC is given below:

Here we applied the pythagorus theorem

AB = 10.8 mm

AC = 1.6mm

BC = ?

Now as we know that

AB^2 + AC^2 = BC^2

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2 years ago

A breakfast chef used different amounts of milk when making pancakes, depending Jon the number of pancakes ordered. The results

OLga [1]

Answer:

Since the 1/2c amounts in the question is 6, thus the amount of milk used by the chef for the six pancakes is:

1/2c multiplied by 6= 3c

Step-by-step explanation:

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3 years ago

Can someone help me with this Geometry question ASAP, thanks!

slega [8]

We are given an isosceles triangle.

An isosceles triangle has corresponding angles of corresponding sides same.

<em>Therefore, other angle is also of (3x+7) degrees.</em>

(5x+13) and (3x+7) makes a linear pair.

Therefore,

(5x+13) + (3x+7) = 180

5x +13 + 3x +7 = 180.

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Subtracting 20 from both sides, we get

8x +20-20 = 180-20.

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Dividing both sides by 8, we get

<h3>x = 20.</h3><h3>Therefore, correct option is 3rd option. </h3>

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2 years ago

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AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

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3 years ago