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eduard
4 years ago
13

Is this a proportion 7/9=21/36

Mathematics
2 answers:
Marat540 [252]4 years ago
5 0

Answer:

No it's not

Step-by-step explanation:

21/7 = 36/9

3 = 4

bixtya [17]4 years ago
5 0

Answer:

No.

Step-by-step explanation:

The fractions are not equal.

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Can you try typing the problem instead of using voice to text. sorry I could not understand
3 0
3 years ago
In order to determine an interval for the mean of a population with unknown standard deviation a sample of 61 items is selected.
Phoenix [80]

Answer:

c. 60

Step-by-step explanation:

Given

n = 61 --- sample

\bar x = 23

Required

Determine the degrees of freedom (df)

This is calculated as:

df = n - 1

df = 61 - 1

df = 60

8 0
3 years ago
What is 4096 written as a power of a number
brilliants [131]
4.096 x 10^3

Hope this helps
7 0
3 years ago
Christine has $875.83 In her savings account the account pays 9% compounded monthly. Christine does not make any deposits or wit
Karolina [17]

Answer: the account earns interest of $40.16

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

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r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 875.83

r = 9% = 9/100 = 0.09

n = 12 because it was compounded 12 times in a year.

t = 6 months = 6/12 = 0.5 year

Therefore,.

A = 875.83(1+0.09/12)^0.5 × 12

A = 875.83(1+0.0075)^6

A = 875.83(1.0075)^6

A = 915.99

The interest that she earns is

915.99 - 875.83 = $40.16

7 0
3 years ago
The length of a line segment is 7. Its end points are (1, 3) and (k, 3). Solve for k. Is there more than one solution? Explain.
Brilliant_brown [7]
Endpoints:\\\\A(1,3)\ and\ B(k,3)\\\\Formula\ for\ length\ of\ line:\\\\
|AB|=\sqrt{(x_b-x_a)^2+(y_b-y_a)^2}\\\\
|AB|=7\\\\7=\sqrt{(k-1)^2+(3-3)^2}\\\\
7=\sqrt{k^2-2k-1}\ \ |^2\\\\
49=k^2-2k-1
49=k^2-2k-1\\\\
-k^2+2k+1+49=0\\\\
-k^2+2k+50=0\\\\ \Delta=b^2-4ac\\\\a=-1,\ b=2,\ c=50 \\\\\Delta=(2)^2-4*(-1)*50=4-=4+200=204\\\\ \sqrt{\Delta}=2\sqrt{51}\\\\k_1=\frac{-b-\sqrt{\Delta}}{2a}\ \ k_1=\frac{-2-2\sqrt{51}}{2*(-1)}=1+\sqrt{51} \\\\\ or\  k_2=\frac{-b+\sqrt{\Delta}}{2a}\ \ k_1=\frac{-2+2\sqrt{51}}{2*(-1)}=1-\sqrt{51}
5 0
3 years ago
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