Answer:
v = 33.8 m/s
Step-by-step explanation:
Given that,
The initial velocity of the truck, u = 0
Acceleration of the truck, a = 3.6 m/s²
Time, t = 9.4 s
We need to find the car's final velocity. Let v is the final velocity.
Using equation of kinematics as follows :
v = u +at
Since, u = 0
Hence, the final velocity of the car is 33.8 m/s.
Janine’s error is that she incorrectly counted the spaces that point C has shifted. Focusing on point C like Janine did, to get to point C’ you would need to shift 3 units to the left and 5 units down. This would make the new translation rule (x-3, y-5) to get from triangle ABC to triangle A’B’C’.
Hi,
a line is define by the following equation : y = ax+b
where a is the slope, and b the value for x = 0
so you have : a*3 +b = 3 for the first point
a*(-5) +b = 4 for second point
so you have a system : 3a+b =3
-5a+b = 4
so : 3a+b -(-5a) -b = 3-4
3a+5a +b-b = -1
8a = -1
a = -1/8
then a = -1/8 so , in remplacing a by it's value in one equation , b is : 3(-1/8) +b = 3
-3/8 +b = 3
b = 3 +3/8
b = 24/8 +3/8
b = 27/8
let's check : 3 (-1/8) + 27/8 = -3/8 +27/8 = 24/8 = 3
first point is correct
-5( -1/8) + 27/8 = 5/8 +27/8 = 32/8 = 4
second point is correct
line is y = -1/8X +27/8
