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White raven [17]
3 years ago
7

3x-2y=4 How do you do this using common core ?

Mathematics
2 answers:
Citrus2011 [14]3 years ago
6 0
First, you graph the equation. Than you do 3x + 2y =4 3 x + 2 y =4. After that you solve for y and y.
bixtya [17]3 years ago
3 0
Graph 3x+2y=4.
3x+2y=4 3<span> x + 2 y = 4.</span>
Solve for y y .
<span>Since 3x 3 ⁢ x does not contain the variable to solve for, move it to the right side of the equation by subtracting 3x 3 ⁢ x from both sides.</span>
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Pls do this.... it will mean a lot to me
Ratling [72]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Write a sine function that has a midline of 3, an amplitude of 5 and a period of 2/7
Stells [14]

sin(kx) has period 2π/k

so, you want

2 + 5sin(16π/7 x)

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7 0
2 years ago
Pls someone help I need this urgently done
Bumek [7]

Answer:

p=3 and q=4 the mistake was in calculating 3q-4q-10=6 let's solve first.

Step-by-step explanation:

if p= 2q-5, substitute the p in the equation3q-2p=6 as

3q-2(2q-5)=6

solve the equation in parentheses :

3q-2(2q-5)\\

multiply  -2 \\ by (2q-5)\\ it will equal to:  3q-4q+10

now we want to let all unknown digits alone, so we will take 10 to the other side with a different sign it will be as:

3q-4q=6-10

now we will solve it:

3q-4q=6-10\\q=-4 at this part, the given equation was wrong in the paper.

we don't want the digit to be negative so we will do it like this:

\frac{-q}{-1} =\frac{-4}{-1 } = q=4

now that we found q we will substitute it to find p\\:

p=2q-5\\q=4\\p=2(4)-5\\p=8-5\\p=3

overall the mistake was in calculating q instead of putting 3q-4q=6-10  

he/she put a different sign in front of the digit like :3q-4q-10=6

so when he/she flipped  -10 it became positive and instead of subtracting he/she added it.  

3 0
2 years ago
My teacher never taught us this so idk how to do it
Verdich [7]

{x}^{3}  = 6\Leftrightarrow  \sqrt[3]{ {x}^{3} }  =  \sqrt[3]{6} \Leftrightarrow x =  \sqrt[3]{6}

6 0
3 years ago
A football team started at the line of scrimmage. On the first play of the drive, the team lost 4 yards. On the second play of t
jolli1 [7]

Answer:

<u>D. Taylor correctly found the distance between –4 and 45, but this number represents the total distance the team moved in both directions, not the team’s total gain.</u>

Step-by-step explanation:

The team only ended up gaining the 45 yards on the second play and had gained -4 on the first play.  45-4≠49, but the total distance between -4 and 45 is 49.

7 0
3 years ago
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