Answer:
T/ T genotype
Explanation:
To know which genotype appears to be associated with a higher prevalence of heart disease, you must know which genotype appeared in the highest percentage in the population tested.
For this, we will do the following calculations.
200 people = 100%
20 people = X
X = (20 * 100) / 200
X = 10%
This means that the C/C genotype appeared in 10% of the tested population.
Now we must to know the percentage of the T / T genotype, we must consider 200 of the 250 people tested.
250 people = 100%
200 people = x
X = (200 * 100) / 250
X = 80%
----
200 people = 80%
30 people = X
X = (30 * 80) / 200
X = 12%
Thus, we can say that the T / T genotype appeared in a higher percentage within the tested population, being considered the genotype that seems to be associated with a higher prevalence of heart disease.
<span>Ringworm is a fungus.</span>
Enzyme synthesis cannot be a function performed by a membrane protein.
<u>Explanation:</u>
Membrane protein is found on the lipid bilayer that surrounds the cell. Enzymes are the globular structures of proteins which are made by the translation of the specific m-RNA in the cytosol of the cell and not by the membrane proteins. While a membrane protein can be used as a pump to transport ions across the membrane, it can be used for cell-cell or cell-matrix adhesion and as a hormone binding protein.
Answer:
10% of progeny would have wild type phenotype
Explanation:
True breeding fly with wild type wings and small eyes: De/De
True breeding fly with downward wings and wild type eyes: dE/dE
Cross between them : De/De X dE/dE = De/dE ( F1 )
Recombination frequency = 20%
Next cross, De/dE X de/de =
De/de = parental = 40%
dE/de = parental = 40%
DE/de = recombinant = 10%
de/de = recombinant = 10%
The third genotype i.e. one of the recombinant genotypes will have the wild type makeup ( DE/de ) hence 10% of flies would have wild type phenotype.
Answer:
A.Both store materials needed by the organism
hope it helps..
