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nignag [31]
3 years ago
10

In my pocket I have 8 quarters and 6 dimes. What fractional portion of the coins in my pocket are dimes

Mathematics
2 answers:
marin [14]3 years ago
7 0

im pretty sure the answer is 3/4

vladimir1956 [14]3 years ago
3 0
6/14 = 3/7 14 is the total amount (8+6)
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Please answer clear i need answers now please
Salsk061 [2.6K]

Answer:

The answers would be:

9: $421.54

10: $872

11: $4,706.66

12: $645.83

13: $626.26

14: $3,981.22

15: $1,110.28

16: $210.50

5 0
3 years ago
What's the answer and show your work by using the funnel method
Paraphin [41]
Answer: i got 44 for the answer
5 0
3 years ago
What is the value of a?<br> a-2 = 3462
Brums [2.3K]

Step-by-step explanation:

a-2=3+6a/3

By cross multiply

3(a-2)=3+6a

3a-6=3+6a

-6-3=6a-3a

-9=3a

a=-3

8 0
4 years ago
Make an argument for why (4^2)^4=(4^4)^2
Eduardwww [97]
I hate when it comes to explaining but I gave it my best!

(4^2)^4 is the same as (4^4)^2 because they’re both being squared and multiplied by the a number equaling to the same number, but written differently.

4^2=16 , whereas 4^4=256
HOWEVER
16^4=65536 and 246^2=65536.

Therefore both equal to the same number. It depends on the exponents, and multiplication. If it were to be a different exponent, then they wouldn’t have been the same
6 0
3 years ago
The R-value of insulation is a measure of its ability to resist heat transfer. For fiber-glass insulation, 3½ inches is rated at
Solnce55 [7]

Answer:

R = \dfrac{16}{5}t + \dfrac{1}{5}

where R is the R-value and t is the thickness in inches.

Step-by-step explanation:

We are given the following in the question:

The  R-value of fiberglass insulation and f its thickness have a linear relation.

Let R be the R-value and t be the thickness. Then, the equation can be written as:

R = at + b

where a and b are constants.

When t = 3.5, R = 11

11 = 3.5a + b

When t = 6, R = 19

19 = 6a + b

Solving the two equation, using the elimination method, we have,

19-11 = 6a + b-(3.5a + b)\\8 = 2.5a\\\\\Rightarrow a = \dfrac{16}{5}\\\\11 = 6(\dfrac{16}{5}) + b\\\\\Rightarrow b = \dfrac{1}{5}

Thus, the linear relationship is given by:

R = \dfrac{16}{5}t + \dfrac{1}{5}

where R is the R-value and t is the thickness in inches.

8 0
3 years ago
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