Answer:
Import java.awt.*;
import java.util.*;
public class Sprhere
{// Instance Data private double surfaceA, volume, r, diameter; //Constructors public Sphere ()
{r = 0;diameter = 0; surfaceA = 0;volume = 0;}
public Sphere (double radius, double d, double SA, double v)
{this. r = radius; this. diameter = d; this. surfaceA = SA;this.volume = v;}
//--------------------------------------------------------------------// Accesors.//--------------------------------------------------------------------public double get Radius()
{return r;}
public double get Diameter()
{return diameter;}
public double get SurfaceA()
{return surfaceA;}
public double get Volume()
{return volume;}
//--------------------------------------------------------------------// Mutators.//--------------------------------------------------------------------
Answer: "N" is considered as the size of the input that is being given in the algorithm.
Explanation: During a problem solving process , a algorithm is used to analyze the problem . Many function and steps are to be taken care of while analyzing algorithm. Among analyzing step, input is also given which is usually zero more than that . An input has a certain size which is given by the initial "N". The input size defines the length of the string for the input.
The option that is note a new technology-related trends in MIS is co-creation of business value.
<h3>Technology and Management Information System:</h3>
Technology and Management Information System is known to be a term that connote the way a person can know or understand data that is obtained from a lot of units and departments of an organization.
Note that It can be used in the area of integration with other types of technology and as such, The option that is note a new technology-related trends in MIS is co-creation of business value.
Learn more about business value from
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ASDF JKL; are the home row keys.
Answer:
Sorted array will be:-
3 5 5 9
Explanation:
In Selection Sort algorithm it sorts the array by repeatedly finds the minimum in the array form the array that is unsorted and swaps it with the value at the first position.
The unsorted array:- 5 3 9 5
In first iteration
minimum is 3.
3 will be swapped with 5.
Now the array is 3 5 9 5
sorted array 3
In second iteration
unsorted array is 5 9 5
sorted array 3 5
and the minimum from it is 5
No swapping will occur.
In third iteration
unsorted array is 9 5
minimum is 5
sorted array 3 5 5
swap it with 9.
Now the array is sorted.
3 5 5 9
