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satela [25.4K]
2 years ago
7

How should you schedule a meeting with someone in another time zone?

Computers and Technology
1 answer:
gavmur [86]2 years ago
7 0

If you know what timezone they're in, try to work out what time in your own timezone your free, then tell the other person to do the same. Tell them what times in your timezone and the other can search up what the time is in their own timezone. If there is a specific time when you are both free, use that.

Ex:

You live in the U.S. but you have a meeting with someone in the U.K. You're only free at 4:00pm-6:00pm and they're only free from 10:00am-11:00am. 11:00am in England is 4:00pm in the U.S. so do at that time!

Hope this helps!

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A spreadsheet program of a computerized version of _______
Romashka-Z-Leto [24]

the answer is "Paper-based Accounting"

8 0
3 years ago
Question is attached as image, please help :>
harkovskaia [24]

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

3 0
3 years ago
Rasheed is memorizing his multiplication tables by using flash cards. He does this frequently enough that eventually he does not
slavikrds [6]

Answer:

Long-term memory

Explanation:

There are two common types of memory - Long-term and short-term.

In short-term memory, information are stored just for a very short time before they are eventually discarded or transferred to the long-term memory. It is sometimes called working memory. For example, short-time memory can be used to remember that a particular event is going to be by 12pm today. After the event, the information might either be discarded or pushed to the long-term memory.

In long-term memory, information are stored for a very long term, almost permanently. For example, long-term memory enables you to remember an event that has taken place in the past. In the case of Rasheed, he has so much learned the multiplication tables in such a way that information on the tables have been stored indefinitely in a part of his brain called hippocampus. Every time he needs the multiplication tables, they are always available. So he is already taking advantage of the long-term memory.

4 0
3 years ago
Language: C
Vikentia [17]

The .cpp code is avaiable bellow

Code:

#include <stdio.h>

#include <string.h>

int main()

{

    char **kW;

    char *fN;

    int nW = 0;

    kW = malloc(5000 * sizeof(char*));

    for (int i = 0; i<5000; i++)

    {

         kW[i] = (char *)malloc(15);

    }

    fN = (char*)malloc(25);

    int choice;

    while (1)

    {

         printf("1) File text to use as cipher\n");

         printf("2) Make a cipher with the input text file and save result as output file\n");

         printf("3) Decode existing cipher\n");

         printf("4) Exit.\n");

         printf("Enter choice: ");

         scanf("%d", &choice);

         if (choice == 1)

         {

             nW = readFile(kW, fN);

         }

         else if (choice == 2)

         {

             encode(kW, fN, nW);

         }

         else

         {

             Exit();

         }

         printf("\n");

    }

    return 0;

}

int readFile(char** words, char *fN)

{

    FILE *read;

    printf("Enter the name of a cipher text file:");

    scanf("%s", fN);

    read = fopen(fN, "r");

    if (read == NULL)

    {

         puts("Error: Couldn't open file");

         fN = NULL;

         return;

    }

    char line[1000];

    int word = 0;

    while (fgets(line, sizeof line, read) != NULL)

    {

         int i = 0;

         int j = 0;

         while (line[i] != '\0')

         {

             if (line[i] != ' ')

             {

                  if (line[i] >= 65 && line[i] <= 90)

                  {

                       words[word][j] = line[i]; +32;

                  }

                  else

                  {

                       words[word][j] = line[i];

                  }

                  j++;

             }

             else

             {

                  words[word][j] = '\n';

                  j = 0;

                  word++;

             }

             i++;

         }

         words[word][j] = '\n';

         word++;

    }

    return word;

}

void encode(char** words, char *fN, int nwords)

{

    char line[50];

    char result[100];

    if (strcmp(fN, "") == 0)

    {

         nwords = readFile(words, fN);

    }

    getchar();

    printf("Enter a secret message(and press enter): ");

    gets(line);    

    int i = 0, j = 0;

    int w = 0, k = 0;

    while (line[i] != '\0')

    {        

         if (line[i] >= 65 && line[i] <= 90)

         {

             line[i] = line[i] + 32;

         }

         w = 0;

         int found = 0;

         while (w<nwords)

         {

             j = 0;

             while (words[w][j] != '\0')

             {

                  if (line[i] == words[w][j])

                  {

                       printf("%c -> %d,%d \n", line[i], w, j);

                       found = 1;

                       break;

                  }

                  j++;

             }

             if (found == 1)

                  break;

             w++;

         }

         i++;

    }

    result[k] = '\n';

}

void Exit()

{

    exit(0);

}

3 0
3 years ago
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blondinia [14]
B

---------------------------------------------
8 0
3 years ago
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