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ivann1987 [24]
3 years ago
7

A chemical compound has a freezing point of -5°C and a boiling point of 97°C. What is the difference between the freezing point

and the boiling point of the chemical compound? °C
Mathematics
1 answer:
rusak2 [61]3 years ago
7 0

Answer:

102°C

Step-by-step explanation:

The chemical compound has a freezing point of -5°C and a boiling point of 97°C.

Since the freezing point is the lower temperature and the boiling point is the higher temperature, the difference between the two temperatures will be subtraction of the freezing point from the boiling point. That is:

97 - (-5) = 97 + 5 = 102°C

The difference between the freezing point and the boiling point is 102°C

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Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

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\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

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