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kolezko [41]
3 years ago
12

When using a straight ladder, it is recommended that the base of the ladder by placed approximately 1/4 the length of the entire

ladder away from the wall.
Mathematics
2 answers:
RUDIKE [14]3 years ago
5 0

Answer:

What is the question?

Step-by-step explanation:

Simora [160]3 years ago
3 0

Answer:

we need to know the lenght of the ladder so we can calculate for u :)

Step-by-step explanation:

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Translate the following verbal expression into a algebraic expression Ten more than the absolute value of a number
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Answer:

x + 10

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Circle A is tangent to circle B.<br> True<br> False
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false

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tangent always touch to the circle

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A golf course charges $16 for a package including the full 18-hole course. The course also sells buckets of
MA_775_DIABLO [31]

16x + 21y = 555

Step-by-step explanation:

Let x be the no. of 18-hole course

And y be the no. of golf balls

16x + 21y = 555

6 0
3 years ago
If 2/3x -1 = 4, then x=
PolarNik [594]

Answer:

15/2

Step-by-step explanation:

2/3x-1=4

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6 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
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