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STatiana [176]
3 years ago
10

I’ll venmo $10 to whoever solves both these pages for me and shows work

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

Donate to the poor maaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaan

Step-by-step explanation:

pls

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Do you need to ask a question, but don't have points.....
horsena [70]
Yes, felt that. thanks and have a lovely day!:D
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Simplify (7ab)squared 0 <br>A) 7<br> B) 1 <br>C) 7ab <br>D)0​
PolarNik [594]

Answer:

The answer to this is B.

Step-by-step explanation:

Anytime a number/variable is squared by a 0, it always equals a 1.

Hope this Helped!!!

~Shane

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3 years ago
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Help me plz???!!!!!?!?!?
zavuch27 [327]

Answer:

H

Step-by-step explanation:

use slope of -2/3 and point (-4.5, 10) as input into the slope-intercept form of a line, which is y = mx + b

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7 0
3 years ago
4s - (s - 12) = 1- (1 - 6s)?
Nadusha1986 [10]

Answer:

s=-4

Step-by-step explanation:

  • combine like terms on each side and get 3s-12=6s
  • subtract 3s from both sides to get -12=3s
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7 0
3 years ago
F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

6 0
3 years ago
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