One zero of f(x)=x^3-2x^2-5x+6 is 1 what are other zeros of the function
2 answers:
Answer:
-2 and 3
Step-by-step explanation:
Given one zero of f(x)=x^3-2x^2-5x+6 to be 1 this means that x-1 is a factor of the polynomial x³-2x²-5x+6
Before we can get the other two factors. We need to divide the polynomial function by x-1 and factorize the resulting quotient as shown in the attachment.
Quotient Q(x) = x²-x-6
Factorizing this function
x²-3x+2x-6 = 0
x(x-3)+2(x-3) = 0
(x+2)(x-3) = 0
x+2 = 0 and x-3 = 0
x = -2 and x= 3
Therefore the other zeros of the function are -2 and 3
You might be interested in
Answer:
Step-by-step explanation:
Given
See attachment for proper format of table
--- Sample
A = Supplier 1
B = Conforms to specification
Solving (a): P(A)
Here, we only consider data in sample 1 row.
In this row:
and
So, we have:
P(A) is then calculated as:
Solving (b): P(B)
Here, we only consider data in the Yes column.
In this column:
and
So, we have:
P(B) is then calculated as:
Solving (c): P(A n B)
Here, we only consider the similar cell in the yes column and sample 1 row.
This cell is: [Supplier 1][Yes]
And it is represented with; n(A n B)
So, we have:
The probability is then calculated as:
Solving (d): P(A u B)
This is calculated as:
This gives:
Take LCM