P^-4 x -5p
In properties of exponents, if the exponent is negative then you move the variable with the negative exponent to the denominators place and it changes to positive and the numerator becomes 1.
p^-4=1/(p^4)
Also, if no exponent is present it is understood to be 1.
Keeping this in mind,
p^-4 x -5p
1/(p^4) x -5p^1 substituted p^-4 by 1/p^4 and added ^1 to -5p
-5p^1/p^4 multiplied-5p^1 to 1
-5/p^3 simplified
Answer:
Step-by-step explanation: 1/4 is 0.25 so 0.25 X 18 = 4.5 so then 18X 5.15 = 81
Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2
tigry1 [53]
Answer:


Step-by-step explanation:
We are given that inner product defined on 

u=(0,-4),v=(5,3)
We have to find the value of <u,v> and d(u,v)
We have 
Substitute the value then we get

Now, 
Using this formula we get

