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faust18 [17]
3 years ago
13

Wht is the measure of the piece she trimmed off

Mathematics
1 answer:
user100 [1]3 years ago
7 0
55 degrees or about 5/12 of the whole shape.
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Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D
Ivahew [28]
Check the picture below.

\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D

\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D

7 0
3 years ago
Can someone please explain how to solve this.<br><br> p^-4 x -5p
solong [7]
P^-4 x -5p

In properties of exponents, if the exponent is negative then you move the variable with the negative exponent to the denominators place and it changes to positive and the numerator becomes 1.

p^-4=1/(p^4)

Also, if no exponent is present it is understood to be 1.

Keeping this in mind,
p^-4 x -5p
1/(p^4) x -5p^1            substituted p^-4 by 1/p^4 and added ^1 to -5p
-5p^1/p^4                     multiplied-5p^1 to 1 
-5/p^3                          simplified 
6 0
3 years ago
NEED HELP ASAP
Lostsunrise [7]

Answer:

0.09

step by step explanation

7 0
2 years ago
It costs $5.15 to buy 1/4 oz of walnuts. how much would it cost to purchase 4.5 oz of walnuts​
nalin [4]

Answer:

Step-by-step explanation: 1/4 is 0.25 so 0.25 X 18 = 4.5 so then 18X 5.15 = 81

3 0
3 years ago
Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2
tigry1 [53]

Answer:

=-12

d(u,v)=2\sqrt{31}

Step-by-step explanation:

We are given that inner product defined on R_n

=3u_1v_1+u_2v_2

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have u_1=0,u_2=-4,v_1=5,v_2=3

Substitute the value then we get

=3(0\cdot5)+(-4)(3)=-12

Now, d(u,v)=\left \|v-u\right \|

Using this formula we get

d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}

d(u,v)=2\sqrt{31}

7 0
3 years ago
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