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SVEN [57.7K]
3 years ago
13

In a local park,a few children were on the monkey bars.the number of children occupying the sides is 1/8 of the number of childr

en playing on the monkey bars,eight children were playing in the sand box if there are 35 children all how many children occupied the slides
Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer: 3 children occupied the slides

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What is 37 1/4 x 24 help me
-BARSIC- [3]

37 and 1 / 4 = 37 * 6 = 74 * 3 = 222

5 0
2 years ago
Urgent!! Will mark brainliest!!
horsena [70]

Answer:

1) x is negative and y is positive ⇒ last answer

2) cotФ = -12/35 ⇒ second answer

3) The right identity is cot²Ф - csc²Ф = -1 ⇒ last answer

Step-by-step explanation:

* For any point (x , y) lies on the terminal side of the angle Ф

 in standard position

* x = cosФ and y = sinФ

- If Ф in the first quadrant, then x , y are positive

∴ All trigonometry functions are positive

- If Ф in the second quadrant, then x is negative , y is positive

∴ sinФ only is positive

- If Ф in the third quadrant, then x is negative , y is negative

∴ tanФ only is positive

- If Ф in the fourth quadrant, then x is positive , y is negative

∴ cosФ only is positive

* Lets solve the problems

∵ Ф = 3π/4 ⇒ (135°)

∴ It lies on the second quadrant

∴ x is negative and y is positive

* Lets revise the reciprocal of sinФ, cosФ and tanФ

- cscФ = 1/sinФ

- secФ = 1/cosФ

- cotФ = 1/tanФ

∵ secФ = -37/12

∴ cosФ = -12/37

∵ π/2 < Ф < π

∴ Ф lies on the second quadrant

∴ cotФ is negative values

∵ tan²Ф = sec²Ф - 1

∵ secФ = -37/12

∴ tan²Ф = (-37/12)² - 1 = 1225/144 ⇒ take√ for both sides

∴ tanФ = ± 35/12

∵ cotФ = ± 12/35

∵ cotФ is negative value

∴ cotФ = -12/35

* In the standard position of the angle Ф the terminal

 of it lies on the unit circle O

- By using Pythagorean theorem

∵ x² + y² = 1

∵ x = cosФ and y = sinФ

∴ cos²Ф + sin²Ф = 1 ⇒ (1)

∴ cos²Ф = 1 - sin²Ф

∴ sin²Ф = 1 - cos²Ф

* Divide (1) by cos²Ф

∴ cos²Ф/cos²Ф + sin²Ф/cos²Ф = 1/cos²Ф

* Remember sin²Ф/cos²Ф = tan²Ф and 1/cos²Ф = sec²Ф

∴ 1 + tan²Ф = sec²Ф ⇒ (2) ⇒ subtract 1 from both sides

∴ tan²Ф = sec²Ф - 1 ⇒ subtract sec²Ф from both sides

∴ tan²Ф - sec²Ф = -1

* Divide (1) by sin²Ф

∴ cos²Ф/sin²Ф + sin²Ф/si²Ф = 1/sin²Ф

* Remember cos²Ф/sin²Ф = cot²Ф and 1/sin²Ф = csc²Ф

∴ cot²Ф + 1 = csc²Ф ⇒ (3) ⇒ subtract 1 from both sides

∴ cot²Ф = csc²Ф - 1 ⇒ subtract csc²Ф from both sides

∴ cot²Ф - csc²Ф = -1

* The right identity is cot²Ф - csc²Ф = -1

3 0
3 years ago
It's 16inches tall and the exact model is 40 feet long
OleMash [197]
Ahh... this is pretty easy!!
.
Locomotive is 40 feet.
.
Model is 16.
.
So?
.
Divide 40 by 16!!
.
What's that?
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2.5. 
.
So your answer choice is 2.5
.
Hope I helped!!
4 0
3 years ago
13. Solve the following:<br> a. 2.68 - 1.44 =<br> b. 5.05 X 0.04 =<br> c. 5.144 = 1.6 =
AURORKA [14]
A) 1.24 B) 0.202 and C) 3.215.
6 0
2 years ago
Read 2 more answers
Y = −2 4x − 3y = 18 solved by substitution please show work so i can understand :)
ycow [4]

Answer:

Step-by-step explanation:

y = -2

4x - 3y = 18

4x - 3(-2) = 18

4x + 6 = 18

4x = 12

x = 3

(3, -2)

5 0
3 years ago
Read 2 more answers
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