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2 years ago

Please help!!!!! Susan walked 1 2/3

Mathematics

1 answer:

Lelu [443]2 years ago

7 0

Answer:

= 1 1/3 miles or 1. 336 miles

Step-by-step explanation:

if 1 1/4 (5/4)hrs = 1 2/3 (5/3)miles or if 1.25hrs = 1.67miles

1 hr = 1 hr x 5/3miles or 1 hr = 1hr x 1.67miles

5/4hrs 1.25hrs

= 1 1/3 miles or  1. 336 miles

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I tried 8 and 1 and this is probably and easy question but can you pls help

Anarel [89]

Answer:

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2 years ago

Subtract 4x from 6x-5.

Ahat [919]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

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now, we can solve integral

$\int \:8\sec \left(t\right)dt$

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now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

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2 years ago

In a random sample of 8 people, the mean commute time to work was 36.5 minutes and the standard deviation was 7.4 minutes. A 98%

ANEK [815]

Answer:

Step-by-step explanation:

Given that

Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes

98% CI using t = (28.7, 44.3) with margin of error as 7.8

Now if sigma = population std dev is known we use Z critical value

Margin of error = 2.33*8.7/\sqrt 8 = 7.167

CI = (36.5 ±7.167)

This is not wider than that used using t distribution

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3 years ago