Question

Will give brainlyest

Answer 1

Answer: (1) 42%, (2) 60%, (3) 75%.

Step-by-step explanation: The calculations are as follows

(1) Given that

P(A) = 0.70,  P(B) = 0.25  and P(A and B) = 0.30 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

$P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.30}{0.70}=0.42.$

Therefore, the answer is 42%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

(2) Given that

P(A) = 0.40,  P(B) = 0.60  and P(A and B) = 0.24 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

$P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.24}{0.40}=0.60.$

Therefore, the answer is 60%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

(3) Given that

P(A) = 0.33,  P(B) = 0.50  and P(A and B) = 0.25 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

$P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.25}{0.33}=0.75.$

Therefore, the answer is 75%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

Thus, the answers are 42%, 602% and 75%.

Answer 2

Answer:

The answers would be 42%, 602% and 75%.

Step-by-step explanation: