Answer:
Step-by-step explanation:
From the given picture,
∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]
m∠ECA = m∠BFD [Given]
m∠ECA + m∠ACB = 180° [Liner pair of angles]
m∠BFD + m∠DFE = 180° [Liner pair of angles]
m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]
m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]
Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]
Answer:
The picture isnt working
Step-by-step explanation:
Answer:
Arc DE = 90°
m<GAB = 82°
Arc DC = 49°
Step-by-step explanation:
Given:
m<EAF = 74°
m<EAD = right angle = 90°
Arc BG = 82°
Required:
Arc DE,
<GAB, and
Arc DC
Solution:
Recall that the central angle measure = the intercepted arc measure.
Therefore:
✔️Arc DE = m<EAD
Arc DE = 90° (Substitution)
✔️m<GAB = arc BG
m<GAB = 82° (Substitution)
✔️Arc DC = m<CAD
Find m<CAD
m<CAD = ½(180 - m<GAB)
m<CAD = ½(180 - 82)
m<CAD = 49°
Arc DC = m<CAD
Arc DC = 49°
Answer:
85 parking spaces
Step-by-step explanation:
Given that :
Parking spaces on floors :
Let first floor = x
Second floor = 2x
Third floor = 2x + 3
Total parking spaces = 428
THEREFORE ;
x + 2x + 2x + 3 = 428
5x + 3 = 428
5x = 428 - 3
5x = 425
x = 425 / 5
x = 85
Hence, there are 85 parking spaces on the first floor
Answer:
c
i think
Step-by-step explanation:
