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3 years ago

How can i solve this?

Mathematics

2 answers:

blagie [28]3 years ago

8 0

Hello!

You can put in the x values and see if you get y

y = (-2)^2 - 2(-2) + 3

y = 4 + 4 + 3

y = 11

The only choice with this D

The answer is D where x is -2 and y is 11

Hope this helps!

laila [671]3 years ago

6 0

If you have a scientific calculator, you can go to tables and plug each one in. whichever table has an equation matching the one provided is the answer... but if you dont have a calculator you can put in one of the x for each table and replace it in the equation then see if it matches with its corresponding y

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HELPPPPP ASP PLZZZZZ

-Dominant- [34]

Answer:

$(f-g)(x)$

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$x^{2} -6x-27-x+9$

$x^{2} -7x-18$

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$=f(x)g(x)$

$(x^{2} -6x-27)(x-9)$

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<u>OAmalOHopeO</u>

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5 0

3 years ago

Imma need sum help please

MrRa [10]

Answer:

Step 5

Step-by-step explanation:

The mistake is in step 5.

The previous step was

$step \: 4 : 2 + 10 \div 2$

The order operations, PEDMAS, must be applied:

We have Addition and Division here,

Using PEDMAS, we must divide first to get:

$step \: 5 : 2 + 5$

We can now add to get:

$step \: 6: 7$

Therefore the mistake occurred at step 5

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3 years ago

Given: JK tangent, KH=16, HE=12 Find: JK.

grin007 [14]

Check the picture below.

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3 years ago

On a sunny day, a flag pole and its shadow form the sides of a right triangle. if the hypotenuse is 35 meters long and the shado

Triss [41]

We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!

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3 years ago

How many meters does 20 yards equal

Yuliya22 [10]

Answer:

Step-by-step explanation:One yard equals 0.9144 meter. Therefore 20 yards = 20 * 0.9144 = 18.288 meters

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3 years ago