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Alexxx [7]
2 years ago
12

How can i solve this?

Mathematics
2 answers:
blagie [28]2 years ago
8 0
Hello!

You can put in the x values and see if you get y

y = (-2)^2 - 2(-2) + 3

y = 4 + 4 + 3

y = 11

The only choice with this D

The answer is D where x is -2 and y is 11

Hope this helps!
laila [671]2 years ago
6 0
If you have a scientific calculator, you can go to tables and plug each one in. whichever table has an equation matching the one provided is the answer... but if you dont have a calculator you can put in one of the x for each table and replace it in the equation then see if it matches with its corresponding y
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I need to know if it’s A B C OR D
Liula [17]

SOLUTION

Consider the property, opposite angle of a cyclic quadrilateral are supplementary

hence

\angle NMP+\angle NOP=180^0

Recall that

\begin{gathered} \angle NMP=\angle M=(8x-24)^0 \\ \text{and } \\ \angle NOP=\angle O=(4x)^0 \end{gathered}

Hnece, we have that

\begin{gathered} \angle M+\angle O=180^0(opposite\text{ angles of a cyclic quadrilateral)} \\ (8x-24)^0+4x^0=180^0 \end{gathered}

Then

\begin{gathered} 8x-24+4x=180 \\ 8x+4x-24=180 \\ 12x-24=180 \\ \text{Add 24 t o both sides } \\ 12x-24+24=180+24 \\ 12x=204 \\ \text{divide both sides by 12} \\ \frac{12x}{12}=\frac{204}{12} \\ \text{Then} \\ x=17 \end{gathered}

Hence

x=17

Since

\begin{gathered} \angle NOP=(4x)^0 \\ \text{substitute the value of x, we have } \\ \angle NOP=4\times17=68^0 \\ \text{Hence } \\ \angle NOP=68^0 \end{gathered}

Therefore

The measure of angle NOP is 68⁰

Answer; 68⁰ (The fourth Option )

5 0
1 year ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
BigorU [14]
You have two 30-60-90 triangles, ADC and BDC.

The ratio of the lengths of the sides of a 30-60-90 triangle is

short leg : long leg : hypotenuse
     1        :  sqrt(3)  :        2

Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC

First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30

Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10

AB = AC - BC = 30 - 10 = 20
6 0
2 years ago
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mel-nik [20]
<span>If two triangles are congruent, then the six corresponding parts are congruent.</span>
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3 years ago
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The difference between x and 4 is greater than 10
bazaltina [42]
X+4>10 is how you would write it.  
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3 years ago
What is the length of BC Round to the nearest tenth
Elenna [48]

Answer:

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7 0
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