What is the seventh term of an arithmetic sequence represented by the rule A(n) = 9+ (n 1)(-5)?

Mathematics

1 answer:

mr Goodwill [35]3 years ago

6 0

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

$y=\frac{1}{4}x-\frac{9}{4}$

Step-by-step explanation:

Given:

Explicit formula for sequence

$A(n)=9+(n-1)(-5)$

To find the 7th term we have to put n=7

So,

$A(7)=9+(7-1)(-5)\\=9+(6)(-5)\\=9-30\\=-21$

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

$y=\frac{1}{4}x-\frac{9}{4}$

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

You might be interested in

I need help, algebra hw

Bogdan [553]

The x-intercept represents the points in which the quadratic function passes through the x-axis. The maximum value represents the ordered pair with the highest range(y-value).
Interval increasing: (Negative Infinity-10)
Interval Decreasing: (10-Negative Infinity)

Part B: 8/5
Note: I am assuming the scale factor of the graph is 2.

8 0

2 years ago

Can anyone help please?

Korolek [52]

Answer:

Step-by-step explanation:

6(2) = 12

12 + 9 = 21

21/3 = 7

7 - 1 = 6 <--- Number that's she's thinking

I tested every number!

8 0