All categories

3 years ago

What is the seventh term of an arithmetic sequence represented by the rule A(n) = 9+ (n 1)(-5)?

Mathematics

1 answer:

mr Goodwill [35]3 years ago

6 0

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

$y=\frac{1}{4}x-\frac{9}{4}$

Step-by-step explanation:

Given:

Explicit formula for sequence

$A(n)=9+(n-1)(-5)$

To find the 7th term we have to put n=7

So,

$A(7)=9+(7-1)(-5)\\=9+(6)(-5)\\=9-30\\=-21$

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

$y=\frac{1}{4}x-\frac{9}{4}$

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

You might be interested in

If f(x) = 3^x + 10x and g(x) = 2x - 4, find (f + g)(x)

allsm [11]

Answer:

3^x + 12x -4

Step-by-step explanation:

f(x) = 3^x + 10x

g(x) = 2x - 4,

(f + g)(x) = 3^x + 10x + 2x - 4

Combine like terms

= 3^x + 12x -4

6 0

2 years ago

Read 2 more answers

A consumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 5% will need repairs

gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

a) Neither will need repair:

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

b) Both will need repair:

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

c) At least one car will need repair

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74) = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0

3 years ago

Write each absolute value in a box to show the order from least to greatest.

arsen [322]

Answer:

|–2| |5| |–8| |11| |–12|

7 0

2 years ago

Read 2 more answers

With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en

GuDViN [60]

Answer:

$P = 0.1447$

Step-by-step explanation:

Given

$n = 7000$ -- total

$d = 180$ --- defective

$r = 6$ --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

$Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}$

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

$Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}$