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3 years ago

Convert 2032four to base 10

1 answer:

6 0

The easiest way is a successive division by 4:

1st division: 2032/4 = 508 and 0 (0 is the  1st Remaining)

2nd division 508/4 = 127 and 0 (0 is the   2nd Remaining)

3rd division 127/4 = 31 and 3 (3 is the   3rd Remaining)

4th division 31/4 = 7 and 3 (3, is the  4th Remaining)

5th division 7/4 = 1 and 3 (3 is the 5th Remaining)

Now you write the last quotient (the 5th) , that is 1 and add to it all remaining starting from the 5th , backward to the 1st remaining,
133300

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What is the value of m in the equation 4m + 2(m + 1) = 9m + 5? <br> −1<br> 1<br> 7<br> 17

ozzi

4m +2(m+1) = 9m +5

4m +2m+2 = 9m +5

6m +2 = 9m +5

6m = 9m+3

-3m = 3

m = -1

4 0

3 years ago

Read 2 more answers

Question 9

IgorC [24]

The answer is (C) the middle one

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%20%5Cfrac%7B%20%7Bx%7D%5E%7Ba%20%2B%20b%7D%20.%20%7Bx%7D%5E%7Bb%20%2B%20c%7D%20

kozerog [31]

Step-by-step explanation:

$\bf \underline{Solution-} \\$

We have to simplify the given expression.

$\rm = \dfrac{ {x}^{a + b} \cdot {x}^{b + c} \cdot {x}^{c + a} }{ {x}^{a} \cdot {x}^{b} \cdot {x}^{c} }$

We know that:

$\rm \longmapsto {x}^{a} \times {x}^{b} = {x}^{a + b}$

$\rm \longmapsto \dfrac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b}$

Therefore, we get:

$\rm = \dfrac{ {x}^{(a + b) + (b + c) + (c + a)}}{ {x}^{a + b + c} }$

$\rm = \dfrac{ {x}^{2(a + b+ c)}}{ {x}^{a + b + c} }$

$\rm = {x}^{2(a + b+ c) - (a + b + c)}$

$\rm = {x}^{a + b + c}$

7 0

2 years ago

Someone help with this midpoint question please

Natali5045456 [20]

Answer: D) (2,0)

Step-by-step explanation:

These are your values.

$(-2,4);(6,-4)$

Remember this means;

$(x_1,y_1);(x_2,y_2)$

The formula for finding the midpoint of a segment is simple. Add both x's and y's and divide them by 2 separately. Or, if you like to follow formulas, here you go.

Let M be midpoint.

$M=\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}$