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3 years ago

Help ;c pls ill make u brainly,

Mathematics

2 answers:

IgorC [24]3 years ago

5 0

Answer:

the answer is 6

Step-by-step explanation:

what you will do is 3 x 4 and that equals 12 and since the triangle is a half you are going to divide by 2

Svetradugi [14.3K]3 years ago

5 0

The answer is 6 it makes sense

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For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

3 0

4 years ago

HELP ME ASAP.

atroni [7]

Answer:

if they are right angles

4 0

4 years ago

mjcaela and julia each improved their yards by planting daylilies and shrubs. they bought their supplies from the same store. mi

evablogger [386]

Answer:

The cost of one day lily = $ 11,

The cost of one shrub = $ 2.

Step-by-step explanation:

Let x be the cost of one day lily and b be the cost of one shrub,

Michaela spent $148 in 12 day lilies and 8 shrubs.

⇒ 12 x + 8 y = 148

⇒ 3 x + 2 y = 37 ----------(1)

While, Julia spent $92 on 6 day lilies and 13 shrubs.

⇒ 6 x + 13 y = 92 --------(2)

2 × Equation (1),

⇒ 6 x + 4 y = 74 --------(3)

Equation (2) - Equation (3),

9 y = 18

⇒ y = 2

By substituting this value in equation (1),

⇒ 3 x + 4 = 37

⇒ 3 x = 33

⇒ x = 11

Hence, the cost of one day lily = x = $ 11

And, the cost of one shrub = y = $ 2

5 0

3 years ago

Given f'(x) = (x-4)(4-2x), find the x-coordinate for relative maximum on the graph of f(x)

antiseptic1488 [7]

Answer:

The coordinate of the relative maximum is x=4.

Step-by-step explanation:

Given that the derivative of the function $f(x)$ is $f'(x) = (x-4)(4-2x)$ , the maxima and minima or the critical points can be found where $f'(x)=0,$ that is:

$f'(x) = (x-4)(4-2x)=0.$

The solutions to this equation are $x=4$ and $x=2.$

Now, if the second derivative $f''(x)$ for a function $f(x)$ is negative at a critical point, then the critical point is the relative maximum.

Therefore we want to see at which of the two critical points is $f''(x)$ negative. The second derivative is:

$\frac{\mathrm{d f'(x)}}{\mathrm{d}x}=f''(x)=-4(x-3).$

Now $f''(4)$ is $-4$ , and $f''(2)$ is $+4$ , therefore we deduce that the relative maxium is located at $x=4$ , because there the second derivative $f''(x)$ is negative.