Given:
The table of values is
Number of Students : 7 14 21 28
Number of Textbooks : 35 70 105 140
To find:
The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.
Solution:
The ratio of number of textbooks to number of students are
All the ratios of the two quantities are proportional and equivalent to the unit rate.
Let y be the number of textbooks and x be the number of students, then
Here, k=5.
Hence the rate of change is constant that is 5.
9.8t^2-49t+40=0
t=(49±√833)/19.6
t≈1.027, 3.97
1.027<t<3.97
Answer:
annhbhhnnnnnnbhhhbbbbbbbbbbbbbbbbbbbbbbbnbnnnnnnnnnnnnnnnnnnnnnn 24cm2
Answer:
f ( 1 )= 20; f ( n )= f (n - 1) + 5, for n > 2
(the > has a line under it)
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
The profit is equal to the number of dolls multiplied by the selling price minus the number of dolls multiplied by the cost of each doll minus the cost of the promotion of the dolls
To make a profit, the number of dolls multiplied by the selling price minus the number of dolls multiplied by the cost of each doll must be greater than the cost of the promotion of the dolls
Let
d -----> the number of dolls
The linear inequality that represent this problem is
Adds 20d both sides
Rewrite
