Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:
Step-by-step explanation:
The A
The answer to your problem is 1300.
Answer:
The simplification is done below.
Step-by-step explanation:
= 
=
= 
Answer:
Δ HGI ≅ ΔEDF
Step-by-step explanation:
Given:
Δ DEF ≅ Δ GHI
From the given congruence statement we can figure out the corresponding sides that are congruent.
The arrangement shows:
So the rearranged statement can be written as:
ΔEDF ≅ Δ HGI
or
∴ Δ HGI ≅ ΔEDF
