Ask question

Ask question

All categories

2 years ago

11

0.003 is 1/10 of??????? PLZ HELP ME !

2 answers:

marysya [2.9K]2 years ago

8 0

.03

You just have to multiply by ten to get what _____ is 1/10 of.

sladkih [1.3K]2 years ago

4 0

0.003 is 1/10 of 0.03.

Just multiply the 0.003 by 10 and you'll get the result. The easiest way to multiply such numbers is to move the dot one position to the right (it would be 2 positions if multiplying by 100, 3 by 1000 etc.). You can do the same with dividing, just remember to move to the left then.

You might be interested in

Find the areas of the trapezoids.

Juliette [100K]

Answer:

12 square units

Step-by-step explanation:

A = 1/2·h(sum of bases)

A = 1/2(4)(2+4)

A = 2(6) which is 12 square units

3 0

3 years ago

The perimeter of a rectangle is dependent on the length of each of its sides. Suppose the base of a rectangle is two more than i

Bezzdna [24]

Perimeter=4h+4

If the base is 2 more than the height, it gives us the equation:
b=h+2

The equation for the perimeter of a rectangle can be though of as 2b+2h, so substituting in (h+2) for b from the first equation, we get 2(h+2)+2h.

This can be simplified to be 2h+4+2h or 4h+4

4 0

3 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

8.21 - 5.19 =<br> Plz show work

elena-s [515]

Answer:

3.02 is the answer

Step-by-step explanation:

BTW, study today! I'm so mad bro

6 0

3 years ago

Read 2 more answers

I need help with his question

Doss [256]

Answer:

27-24i

Step-by-step explanation:

It is trust me:)

3 0

2 years ago