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Daniel [21]
3 years ago
11

Yesenia is investing money in the stock market, in which she is looking at growth over the first month. She invested $300 and in

the first month, earned 1.25% returns. How much money does she now have after the first month?
Mathematics
2 answers:
mixer [17]3 years ago
7 0

Answer:

1.25 because when in a calculator i add 1.25% i subtract 300 and that is all that is left.

melamori03 [73]3 years ago
7 0

Answer:

3.75

Step-by-step explanation:

\frac{x}{300} =  \frac{1.25\%}{100}

x \times 100 = 100x

300 \times 1.25 = 375

375 \div 100 = 3.75

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Write a correct equation for the function whose graph is shown.
Rom4ik [11]

Answer:

\displaystyle y=-2sin(6t)

Step-by-step explanation:

<u>Sinusoid</u>

The shape of a sinusoid is well-know because it describes a curve with a smooth and periodic oscillation. The sine and cosine are the two trigonometric functions in which the graph matches the description of a sinusoid. The sine can be identified because its value is zero at time zero.

The graph shown in the figure corresponds to a sine. The other characteristics of the sine function are

* It completes a cycle in2\pi radians

* It has a maximum of 1 and a minimum of -1

* It's increasing for a quarter of the cycle, decreasing for half of the cycle, and increasing for the remaining quarter of the cycle

* The equation is

y=Asin(wt)

The function starts decreasing for the first quarter, which only is possible if the amplitude A is negative. We can also see the maximum and minimum values are 2 and -2 respectively. This means the amplitude is A=-2

We can also see the function completes 3 cycles in t=\pi radians or 6 cycles in 2\pi radians. Or, equivalently

wt=12\pi

w(2\pi)=12\pi

\displaystyle w=\frac{12}{2}=6\ rad/sec

Thus, the function can be expressed as

\boxed{\displaystyle y=-2sin(6t)}

6 0
3 years ago
In the picture above, ∠3 and ∠7 are ______ <br> angles which are _____.
alexandr402 [8]

Answer:

Corresponding

Equal, Congruent

Step-by-step explanation:

7 0
3 years ago
Julia rides her horse 18 km with a constant speed of 6km/hr and another 24 km with a constant speed of 12 km/hr. What is her ave
nlexa [21]

Answer:

8.4 km/hr.

Step-by-step explanation:

We have been given that Julia rides her horse 18 km with a constant speed of 6 km/hr.

Let us find the time taken by Julia to cover a distance of 18 km.

\text{Time}=\frac{\text{Distance}}{\text{Speed}}

\text{Time taken to cover 18 km}=\frac{18\text{ km}}{\frac{6\text{km}}{\text{hour}}}

\text{Time taken to cover 18 km}=\frac{18\text{ km}}{6}\times\frac{\text{hour}}{\text{km}}

\text{Time taken to cover 18 km}=\frac{18}{6}\times\text{hour}

\text{Time taken to cover 18 km}=3\text{ hour}

We are also told that she rides another 24 km with a constant speed of 12 km/hr.

Let us find the time taken by Julia to cover a distance of 24 km.

\text{Time taken to cover 24 km}=\frac{24\text{ km}}{\frac{12\text{km}}{\text{hour}}}

\text{Time taken to cover 24 km}=\frac{24\text{ km}}{12}\times\frac{\text{hour}}{\text{km}}

\text{Time taken to cover 24 km}=\frac{24}{12}\times\text{hour}

\text{Time taken to cover 24 km}=2\text{ hour}

Since we know that \text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}.

Upon substituting our values in above formula we will get,

\text{Julia's average speed}=\frac{18\text{ km}+24\text{ km}+}{3\text{ hour}+2\text{ hour}}

\text{Julia's average speed}=\frac{42\text{ km}}{5\text{ hour}}

\text{Julia's average speed}=\frac{8.4\text{ km}}{\text{ hour}}

Therefore, Julia's average speed is 8.4 km per hour.


5 0
4 years ago
Yolanda finished 3/4of 10 1/2mile race how many mile sdid she complete
Mila [183]

Answer:

She completed 7.5 3/8 miles of the race.

Step-by-step explanation:

This can be solved with multiplication.

10 * 3/4 = 7.5

1/2 * 3/4 = 1 * 3/2 * 4 = 3/8

7 0
3 years ago
Sophie drove 189 miles in 7 hours. If she continued at the same rate, how long would
Mazyrski [523]

Answer:

8 hours

Step-by-step explanation:

if 189 miles= 7 hours. what about 216 miles.you cross multiply

6 0
3 years ago
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