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Elena-2011 [213]
3 years ago
5

Integration of (cosec^2 x-2005)÷cos^2005 x dx is

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate 
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then, 
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
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IF THE TRIANGLES IN THE ABOVE FIGURE ARE PROPORTIONAL, WHATS THE LENGTH OF SIDE B?
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<h3>Answer: choice B) 36</h3>

=================================================

Explanation:

The vertical sides, when read from left to right, can be divided to get this fraction: 9/90

Following the same order and direction, we divide the slanting corresponding sides to get: b/360

The fractions we constructed are equal to one another, as the triangles are said to be proportional.

We have the fraction 9/90 = b/360

Lets cross multiply and solve for b

--------------------

9/90 = b/360

9*360 = 90*b

3240 = 90b

90b = 3240

90b/90 = 3240/90

<h3>b = 36</h3>

--------------------

A quick way to do this may be to notice how the jump from 9 to 90 is "times 10" so the jump from b to 360 is also "times 10". Think in reverse to divide 360 over 10 and we land on 36 as our answer. This line of thinking does not work as simple for all proportional problems.

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