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Naily [24]
3 years ago
14

How can you write the equation for a linear function if you know only two ordered pairs for the function?

Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

Use the two ordered pairs to find the slope, <u>m</u>.

Then substitute <u>one set of ordered pairs</u> and <u>m</u> into y = mx + b to solve for <u>b</u>

Step-by-step explanation:

If we are given two ordered pairs of a function and we need to write an equation that represents the linear function, first, what we need to do is to use the two ordered pair to find the slope, m, using the formula, m = \frac{y_2 - y_1}{x_2 - x_1}.

After getting the slope (m), find the value of the y-intercept (b), by substituting the value of one of the ordered pairs and the slope value (m) into y = mx + b.

Once the value of m and b is known, plug in the value of m and b into y = mx + b to derive the equation of the linear function.

Deffense [45]3 years ago
4 0

Answer:

Use the two ordered pairs to find the slope,  <u>m </u>.

Then substitute <u> m</u>  and <u> one set of ordered pairs</u>  into y = mx + b to solve for  <u>b </u>.

Step-by-step explanation:

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There are three kids. The sum of individual squares of their body weights (2 + 2 + 2) is 100. The sum of the product of their we
Mashcka [7]

Answer:

20

Step-by-step explanation:

Givens

Let child one = x

Let child two = y

Let child three = z

Equations

x^2 + y^2 + z^2 = 100

xy + xz + yz = 150

Solution

There's a trick here. The square of their weights added together is equal (with some modification) to the given conditions. Start by squaring (x+y+z).

(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz

Take out 2 as a common factor from the last three terms.

(x + y + z)^2 = (x^2 + y^2 + z^2+ 2(xy + xz + yz) )

Substitute the given conditions into the equation. (x^2 + y^2 + z^2) = 100 and 2*(xy + xz + yz) = 2 * 150

(x + y + z)^2 = 100 + 2*150

(x + y + z)^2 = 100 + 300

(x + y + z)^2 = 400

Take the square root of both sides.

sqrt(x+y+z)^2 = sqrt(400)

x + y + z = 20

Note

This answer tells you nothing about the values of x y and z. On the other hand it does not ask for the values of x y and z.

4 0
3 years ago
The surface area of the moon is 37,932,330km squared. Calculate the side length of a square with the same area.
kumpel [21]
Area of a square = length²
length² = 37 932 330
length = √37 932 330
= 6160 km (to three signifcant figures)

The side length of a square with the same area would then be 6160 km.
8 0
3 years ago
Read 2 more answers
Rewrite the following equation as a function of x 2x^(4)-625-500=0
Gala2k [10]
Correct choice is D! :)
4 0
3 years ago
Read 2 more answers
Need some help asap...............
Agata [3.3K]

Answer:

<h2>39.94 cm</h2>

Solution,

ABCD is a rectangle.

Given,

AC= 64 cm

AB= 50 cm

To find: Value of other side of TV

since, ABCD is a rectangle

<B= 90°

<h3>Using Pythagorean theorem:</h3>

{ac}^{2}  =  {ab}^{2}  +  {bc}^{2}  \\  {64}^{2}  =  {50}^{2}  +  {bc}^{2}  \\  {bc}^{2}  =  {64}^{2}  -  {50}^{2}  \\  {bc}^{2}  = 4096 - 2500 \\  {bc}^{2}  = 1596 \\ bc =  \sqrt{1596}  \\ bc = 39.94 \: cm

Hope this helps...

Good luck on your assignment..

3 0
3 years ago
Please help ....this is due tomorrow
marshall27 [118]

A) 0.15 times $2,570 = $412.50

B) $122.85 times 2( 12 ) = $2,948.40

C) $2,570

D) All together it's  $2,948.40 + $2,570 = $5,518.40

For D I didn't add the down payment because it's not an additional charge.

I only did the first one because I don't know if you want me to finish the rest.

Hope I helped :)

5 0
3 years ago
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