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eimsori [14]
3 years ago
14

For which points is the y coordinate less that -1.5

Mathematics
1 answer:
Masja [62]3 years ago
3 0
The bottom 2.

I can’t see the point names cause its blurry but those bottom 2 points should be the answers.

Y coordinates are how high or low
X coordinates are how far left or right

Brainliest if this helps?
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My club has 25 members. In how many ways can I choose members to form a 4-person executive committee?
Rama09 [41]

Answer:  12650

Step-by-step explanation:

It can be done in C25  4 =  25!/(25-4)!/4!= 25!/21!/(2*3*4)=

=22*23*24*25/24=22*23*25= 12650 variants

4 0
3 years ago
The Lovin lemon company sells a 4 gallon jug of lemonade for $24 dollars. The sweet and Sour company sells an eight pack of 1 qu
aivan3 [116]

Answer:

lovin lemon co. sells 1 gallon for 24/4 = $6

sweet & sour co. sells 8 qt = 2 gallons for 16/2 = $8

3 0
3 years ago
what are the coordinates of that center of a circle if the endpoints of its diameter are a(8,-4) and b(-3,2)?
11111nata11111 [884]
You need to add 8 and -3 together to get 5 and divide 5 by 2 to get 2.5
That is the x coordinate
You then need to add 2 and -4 together to get -2 and divide by 2 to get -1
This is the y coordinate
(2.5,-1)
8 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
Express in the form of p/q :<br><br> (i) 0.12▁3 (ii) 0. ▁621 (iii) 2.2▁18​
konstantin123 [22]

Answer:

1)0.123( bar on 3)

Let X = 0.123 ( bar on 3)

Then X = 0.1233 --------(1)

Multiply equation (1) by 100 we get,

100X = 12.33 --------(2)

Again multiply equation (2) by 10 we get,

1000X = 123.33 -------(3)

Subtract equation (2) from equation (3) we get,

1000X = 123.33

100X = 12.33

____________

900X = 111

X = 111/900

Hence,

0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.

6 0
3 years ago
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