(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Answer:
C. (3x)^2 - (2)^2
Step-by-step explanation:
Each of the two terms is a perfect square, so the factorization is that of the difference of squares. Rewriting the expression to ...
(3x)^2 - (2)^2
highlights the squares being differenced.
__
We know the factoring of the difference of squares is ...
a^2 -b^2 = (a -b)(a +b)
so the above-suggested rewrite is useful for identifying 'a' and 'b'.
Answer:
The answer to the promblem is -7
Answer:
200,000 i don't know apologies if it's wrong
Step-by-step explanation:
100,000*.20*10
200,000*10
200,000
Answer:
Step-by-step explanation:A.
