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3 years ago

Get this correct i will give u brainliest.

Mathematics

1 answer:

castortr0y [4]3 years ago

4 0

Answer:

x = - 2, y = - 8

Step-by-step explanation:

Given the 2 equations

13x - 6y = 22 → (1)

x = y + 6 → (2)

Substitute x = y + 6 into (1)

13(y + 6) - 6y = 22 ← distribute and simplify left side

13y + 78 - 6y = 22

7y + 78 = 22 ( subtract 78 from both sides )

7y = - 56 ( divide both sides by 7 )

y = - 8

Substitute y = - 8 into (2) and evaluate for x

x = - 8 + 6 = - 2

Thus x = - 2, y = - 8

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one end of a tent is a triangle. the height of the triangle is 1.5 m and the base is 2.5 m. what is the area of the triangle?

Anarel [89]

Answer:

1.5×2.5/2=1.875.

Step-by-step explanation:

We all know that area of triangle is base into hight upon 2.

3 0

1 year ago

cynthia invests some money in a bank which pays 5% compound interest per year. She wants it to be worth over £8000 at the end of

exis [7]

Answer:

The smallest amount is $\£6,911$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=3\ years\\ A=\£8,000\\ r=5\%=5/100=0.05\\n=1$

substitute in the formula above

$8,000=P(1+\frac{0.05}{1})^{1*3}$

solve for P

$8,000=P(1.05)^{3}$

$P=8,000/(1.05)^{3}$

$P=\£6,910.70$

Round to the nearest pound she can invest

The smallest amount is $\£6,911$

6 0

3 years ago

What is the ratio of lines b : c if A is 77°

stellarik [79]

Answer:

3rd option

Step-by-step explanation:

the ratio of b : c is the cos77° , that is

cos77° = $\frac{adjacent}{hypotenuse}$ = $\frac{b}{c}$ ≈ 0.224951054.

3 0

2 years ago

Write the polynomial in standard form. <br> 5z + 2z^3 - z^2 + 3z^4

pochemuha

Answer:

the standard form of this equation will be 3z^4 + 2z^3 - z^2 + 5z

Step-by-step explanation:

as much as I would like to, I'm really not that good at explaining things

5 0

3 years ago

The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we

Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

Sigma, σ = 0.200 kg

Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13$

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

Test statics :

$Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}}$

$Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}}$

$=\frac{1.82}{0.04}$

= 45.5

P-value = 2 x P(Z > 45.5)

= 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0

3 years ago