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2 years ago

The sum of Sasha’s and Natalie’s ages is 31. Twice Natalie’s age is 11 years more than Sasha’s age. Find each of their ages

Mathematics

1 answer:

ZanzabumX [31]2 years ago

6 0

Answer:

Natalie's age is 14

Sasha's age is 17

Step-by-step explanation:

Let

Sasha's age be "s", and

Natalie's age be "n"

Sum of Sasha and Natalie is 31:

s + n = 31

Twice Natalie is 11 more than Sasha:

2n = s + 11

We ca solve this equation for s first:

s = 2n - 11

We put this into first equation and solve for n first:

s + n = 31

2n - 11 + n = 31

3n = 31 + 11

3n = 42

n = 42/3 = 14

Natalie's age is 14

Also, s = 2n - 11

s = 2(14) - 11

s = 28 - 11

s = 17

Sasha's age is 17

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2 years ago

Which statement describes the effect on the parabola f(x)=2x•x-5x+3 when changed to f (x)= 2x•2-5x+1

o-na [289]

Answer:

The parabola is translated down 2 units.

Step-by-step explanation:

You have the parabola f(x) = 2x² – 5x + 3

To change this parabola to f(x) = 2x² - 5x + 1, you must have performed the following calculation:

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If p> 0 and q> 0, the parabola shifts p units to the right and q units up.
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If p <0 and q <0, the parabola shifts p units to the left and q units down.

In the expression A it can be observed then that q = -2 and is less than 0. So the displacement is down 2 units.

This can also be seen graphically, in the attached image, where the red parabola corresponds to the function f(x) = 2x² – 5x + 3 and the blue one to the parabola f(x) = 2x² – 5x + 1.

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2 years ago

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2 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

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Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

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$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$