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gizmo_the_mogwai [7]
3 years ago
12

A red candle is 11 2/5 inches tall. The label claims that the candle will melt 1 1/8 inch every hour it burns. If the label is c

orrect, for how many hours will the candle burn?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0
11\frac{2}{5}\ inches\ burn\ in\ x\ hours\\\\
1\frac{1}{8}\ inches\ burn\ in\ 1\ hour\\\\cross\ multiplication\\\\
11\frac{2}{5}=1\frac{1}{8}x\ \ \ \ | divide\ by\ 1\frac{1}{8}\\\\
\frac{\frac{57}{5}}{\frac{9}{8}}=x\\\\\frac{57}{5}*\frac{8}{9}=x\\\\
x=\frac{456}{45}=10\frac{2}{15}\\\\
Candle\ will\  burn\ in \ 10\frac{2}{15}\ hours.
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Illusion [34]

Answer:

The volume of this pyramid is 16 cm³.

Step-by-step explanation:

The volume V of a solid pyramid can be given as:

\displaystyle V = \frac{1}{3} \cdot b \cdot h,

where

  • b is the area of the base of the pyramid, and
  • h is the height of the pyramid.

Here's how to solve this problem with calculus without using the previous formula.

Imaging cutting the square-base pyramid in half, horizontally. Each horizontal cross-section will be a square. The lengths of these squares' sides range from 0 cm to 3 cm. This length will be also be proportional to the vertical distance from the vertice of the pyramid.

Refer to the sketch attached. Let the vertical distance from the vertice be x cm.

  • At the vertice of this pyramid, x = 0 and the length of a side of the square is also 0.
  • At the base of this pyramid, x = 3 and the length of a side of the square is 4 cm.

As a result, the length of a side of the square will be

\displaystyle \frac{x}{3}\times 4 = \frac{4}{3}x.

The area of the square will be

\displaystyle \left(\frac{4}{3}x\right)^{2} = \frac{16}{9}x^{2}.

Integrate the area of the horizontal cross-section with respect to x

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  • to the base, where x = 3.

\displaystyle \begin{aligned}\int_{0}^{3}{\frac{16}{9}x^{2}\cdot dx} &= \frac{16}{9}\int_{0}^{3}{x^{2}\cdot dx}\\ &= \frac{16}{9}\cdot \left(\frac{1}{3}\int_{0}^{3}{3x^{2}\cdot dx}\right) & \text{Set up the integrand for power rule}\\ &= \left.\frac{16}{9}\times \frac{1}{3}\cdot x^{3}\right|^{3}_{0}\\ &= \frac{16}{27}\times 3^{3} \\ &= 16\end{aligned}.

In other words, the volume of this pyramid is 16 cubic centimeters.

5 0
3 years ago
What type of function is represented in the table? x|0|1|2|3|4|5|
mezya [45]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x).
scZoUnD [109]
<h3>Answer:   2x^2 + 6x - 4</h3>

=================================

Work Shown:

f(x) - g(x) = [ f(x) ] - [ g(x) ]

f(x) - g(x) = ( 3x^2+x-3) - ( x^2-5x+1 )

f(x) - g(x) = 3x^2+x-3 - x^2+5x-1

f(x) - g(x) = (3x^2-x^2) + (x+5x) + (-3-1)

f(x) - g(x) = 2x^2 + 6x - 4

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Answer:

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Step-by-step explanation:

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