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Nina [5.8K]
3 years ago
7

What is the smallest particle of a covalent compound that has the properties of that compound?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
5 0
The smallest particle is the white blood cells because they are the ones that help you breathe
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If 1.80 moles of NaCl was dissolved in enough water to make 3.60 L of solution, what is the Molarity?
sweet-ann [11.9K]

Answer:

0.5M

Explanation:

The equation for molarity is:

  • M = \frac{mol}{liters} ; where the "M" stands for molarity, the "mol" stands for moles of solute and the "liters" means the volume in liters of solution.

We are given that there are:

  • 1.80 moles of NaCl (the moles of solute)
  • 3.60 Liters of solution (the volume in liters of solution)

Now we just plug those numbers into the formula and get our answer:

  • M= \frac{1.80mol}{3.60L}= 0.5M

After doing the math and dividing the moles of solute by the liters of solution, we get that the molarity of the solution is 0.5M.

8 0
3 years ago
Cl2 + NaBr<br>which two elements will trade places?​
anygoal [31]
The hallogens chloride with br
5 0
3 years ago
How many moles are in 5.0 x 10 *23 atoms of iron?
tamaranim1 [39]
1 mole ------------ 6.02 x 10²³ atoms
? moles ----------- 5.0 x 10²³ atoms

moles = 5.0 x 10²³ / 6.02 x 10²³

= 0.830 moles

hope this helps!
7 0
3 years ago
Evaluate ( a=2 b=3)...3a - 2b =​
skad [1K]

Hey!

---------------------------------------------------

Steps To Solve:

~Substitute

3(2) - 2(3)

~Subtract

6 - 6

~Simplify

0

---------------------------------------------------

Answer:

\Large\boxed{\mathsf{0}}

---------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
Read 2 more answers
How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0
3 years ago
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