In general, we have this rate law express.:
![\mathrm{Rate} = k \cdot [A]^x [B]^y](https://tex.z-dn.net/?f=%5Cmathrm%7BRate%7D%20%3D%20k%20%5Ccdot%20%5BA%5D%5Ex%20%5BB%5D%5Ey)
we need to find x and y
ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).
then we go to compare two experiments in which only one concentration is changed
compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]
Δ[B]= 0.3 / 0.1 = 3
now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:
ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...
solve for y in the equation
![\Delta \mathrm{Rate} = \Delta [B]^y](https://tex.z-dn.net/?f=%5CDelta%20%5Cmathrm%7BRate%7D%20%3D%20%5CDelta%20%5BB%5D%5Ey)

To this point,
![\mathrm{Rate} = k \cdot [A]^x [B]^1](https://tex.z-dn.net/?f=%5Cmathrm%7BRate%7D%20%3D%20k%20%5Ccdot%20%5BA%5D%5Ex%20%5BB%5D%5E1%20)
do the same to find x.
choose two experiments in which only the concentration of B is unchanged:
Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4
solve for x for
![\Delta \mathrm{Rate} = \Delta [A]^x](https://tex.z-dn.net/?f=%5CDelta%20%5Cmathrm%7BRate%7D%20%3D%20%5CDelta%20%5BA%5D%5Ex)

the rate law is
Rate = k·[A]²[B]
Selenium is a non metal, radon is a noble gas, silicon is a metalloid, and sulphur is a non metal. Hafnium is a transition metal.
To convert milliliters to liters, you should divide the milliliters by 1000. When we do that here, we will see that there are 0.0456 liters in 45.6 milliliters.
Second choice is electron cloud and first is a discrete amount thst is fixed
Answer:
Blue color of iodine-starch complex is disappear upon hysrolysis
Explanation:
Starch:
Starch is a polysaccharide
it is energy reservoir.
starch is made of monomers of glucose in a chain form.
The simplest form of starch is linear polymer amylose.
Iodine Test:
In this test iodine solution added to the solution to check the presence of starch.
Iodine solution = elemental iodine + KI
Result of Iodine Test:
when the iodine solution (I₃⁻) is added to a solution it show two types of result.
if the starch is present this I₃⁻ form a complex with amylose chain of starch and impart a dark blue color.
if starch is not present then the color will be orange or yellow.
Hydrolysis of Starch:
Hydrolysis of starch is carried out by an enzyme, this enzyme break down the starch into simpler sugar molecule.
So,
When the hydrolysis of starch occur the starch convert to glucose. Then the blue color of starch and iodine complex formed during iodine test is disappear that will be the indication of hydrolysis of starch.